Django url.py regex not working

Question

I am trying to catch all URLs from the safer app and send them to a catch all view; for example: http://127.0.0.1:8000/saferdb/123
http://127.0.0.1:8000/saferdb/12

I think I have an issue with my reg ex in url.py:

from django.conf.urls import url
from . import views

app_name = 'saferdb'
urlpatterns = [
    url(r'^/$', views.index, name='index'),
    url(r'^(?P<pk>[0-9]+)/$', views.detail, name='detail'),
]

Views.py is the sample code from the django tutorial:

from django.shortcuts import render

# Create your views here.
from django.http import HttpResponse
from .models import Question

def index(request):
    latest_question_list = Question.objects.all()[:5]
    output = ', '.join([q.DOT_Number for q in latest_question_list])
    return HttpResponse(output)


def detail(request, question_id):
    return HttpResponse("You're looking at question %s." % question_id)

I noticed that /saferdb/ will not work unless the reg ex contains a slash: r'^/$' instead of r'^$' as shown in the django tutorial.

add a / at the end of the /saferdb in the main urls.py file. — Vijesh Venugopal
– Vijesh Venugopal, Commented Dec 7, 2017 at 13:50

rajkris · Accepted Answer · 2017-12-07 13:53:57Z

1

Please add '/' at the end of url in root urls.py of 'safer' app, something similar to this:

url(r'^saferdb/', include('saferdb.urls', namespace='saferdb'))

answered Dec 7, 2017 at 13:53

rajkris

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