Sort(), confusing about condition in comparision function

Question

I get this code from a basic javascript lesson on Codewar, but I don't understand how it work, I tried one by one condition but it doesn't show output as I expected. Thank you so much.

var arr=[1,2,3,4,5,6,100,999]
arr.sort((a,b)=>{
  if (a%2==b%2) return a-b;
  if (a%2>b%2) return -1;
  return 1;
})
console.log(arr)

//output: [ 1, 3, 5, 999, 2, 4, 6, 100 ]

Because I don't understand it so I saw it a little strange. Now I got it. — Tin Le
– Tin Le, Commented Dec 9, 2017 at 2:50

Maged Milad · Accepted Answer · 2017-12-08 18:54:59Z

1

it should print the odd numbers first then even numbers, each is sorted

if (a%2==b%2) return a-b; if a, b are both even or both odd then sort them in increasing order

if (a%2>b%2) return -1; else if they are different [ one odd and the other is even ] put the odd numbers first

else a, b are equal

edited Dec 8, 2017 at 18:54

answered Dec 8, 2017 at 18:49

Maged Milad

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1 Comment

Tin Le Over a year ago

Thank u for your explaination. I help me understood how it works.

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