I'm new to c# development. I have a label on the form that shows the following sequence 1,1,1,3,5,9 and a button. When the button is clicked I want it to add the sequence of numbers to the label. For example : I know how the the above sequence works 1+1+1=3,3+1+1=5,5+3+1=9 ,so it calculates the previous 3 numbers to add to the sequence. What I'm trying to achieve is when the button is clicked each time it must show the next numbers that come in ex: after 9, will be 17 because 3+5+9=17 And so on... It must go up every time it's clicked .your help will be highly appreciated.
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2It's very hard to determine exactly how much you have done so far. Do you have a function that takes the existing list of numbers and calculates what the new one should be? Do you know how to convert that array into a string you can show on a label? Do you know where to store the list of numbers so it's available in the button click handler and keeps its value between clicks?Dylan Nicholson– Dylan Nicholson2017-12-09 06:51:53 +00:00Commented Dec 9, 2017 at 6:51
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Are you saying you want your algorithm to look at a series of numbers and figure out what the pattern is? Or is the pattern always the same?BJ Myers– BJ Myers2017-12-09 06:53:11 +00:00Commented Dec 9, 2017 at 6:53
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@Dylan no I don't have any function. I know that it will go behind the button click event. The 1,1,1,3,5,9 I just added it to the label. Not sure how to add an algorithm to calculate the next numbers.Sarah– Sarah2017-12-09 08:23:07 +00:00Commented Dec 9, 2017 at 8:23
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@bj myers I want it to figure out what the algorithm is And then calculate it. Then I must get the nth instance of the sequence where n divided by x has no remainder.Sarah– Sarah2017-12-09 08:26:45 +00:00Commented Dec 9, 2017 at 8:26
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@Sarah please see the algorithm below and let me know if this is what you were looking for.Jamin– Jamin2017-12-09 08:30:40 +00:00Commented Dec 9, 2017 at 8:30
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1 Answer
I believe the algorithm you are looking to do is create a List<int> to contain the ints that are going to be used on the label.
List<int> numbers = new List<int>();
Then you are trying to .Add the first 6 starting numbers into the list like so:
numbers.Add(1);
numbers.Add(1);
numbers.Add(1);
numbers.Add(3);
numbers.Add(5);
numbers.Add(9);
Once the user clicks the button, change the original label's text information to also have the result of adding the last three elements of int within the List<int>.
This can be done by using .Count to get the length/size of the List<int> in the following fashion:
int x = numbers[numbers.Count - 1]; //Last number/element in List
int y = numbers[numbers.Count - 2]; //Second to last
int z = numbers[numbers.Count - 3]; //Third to last
int result = x + y + z; //sum of last number plus second to last number plus third to last number
Don't forget to .Add the result of adding the last three elements to the end of the List<int>.
numbers.Add(result);
Once you have the result added, you can set the label's .Text value to the joining of a string in the following way:
numbersLabel.Text = string.Join(", ", numbers);
A sample demonstration of a class that contains a button, and a label that accomplishes this algorithm is below.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApp1
{
public partial class LabelAlgorithm : Form
{
public List<int> numbers = new List<int>();
public LabelAlgorithm()
{
numbers.Add(1);
numbers.Add(1);
numbers.Add(1);
numbers.Add(3);
numbers.Add(5);
numbers.Add(9);
InitializeComponent();
numbersLabel.Text = string.Join(", ", numbers);
}
private void SubmissionButton_Click(object sender, EventArgs e)
{
int x = numbers[numbers.Count - 1];
int y = numbers[numbers.Count - 2];
int z = numbers[numbers.Count - 3];
int result = x + y + z;
numbers.Add(result);
numbersLabel.Text = string.Join(", ", numbers);
}
}
}
Output to Label:
1, 3, 5, 9, 17, 31, 57, 105, 193, 355, 653, 1201, 2209, 4063...
1 Comment
Sarah
Thank you,that makes sense.