How can I transform a jquery object into a php array?

Question

I created a jquery object via $("input").serializeArray();

This is my output:

0: Object { name: "id", value: "9" }
1: Object { name: "name", value: "Fred" }
2: Object { name: "quantity", value: "1" }

I send this object via ajax to my php page. There I get it via $_POST['myarray']. The output is:

[0]=>
  array(2) {
    ["name"]=>
    string(2) "id"
    ["value"]=>
    string(1) "9"
  }
  [1]=>
  array(2) {
    ["name"]=>
    string(4) "name"
    ["value"]=>
    string(14) "Fred"
  }
  [2]=>
  array(2) {
    ["name"]=>
    string(8) "quantity"
    ["value"]=>
    string(1) "1"
  }

But the output I would need is:

      array(3) {
        ["id"]=>
        string(1) "9"
        ["name"]=>
        string(1) "Fred"
        ["quantity"]=>
        string(1) "1"
      }

Rory McCrossan · Accepted Answer · 2017-12-13 15:22:01Z

2

To get the required data structure in PHP you need to send a single object from your JS code in this format:

{ 
  id: "9",
  name: "Fred",
  quantity: "1" 
}

To do that you can build a new object using the keys of the objects within the current array, like this:

var serializedForm = [
  { name: "id", value: "9" },
  { name: "name", value: "Fred" },
  { name: "quantity", value: "1" }
];
  
var o = {};
serializedForm.forEach((k) => {
  o[k.name] = k.value;
});

console.log(o);

answered Dec 13, 2017 at 15:22

Rory McCrossan

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Comments

William · Accepted Answer · 2017-12-13 15:39:16Z

2

On the server side, you can pick the key/value pairs in a loop and create the array format you desire:

$formObj = $_POST['myarray'];
$myObj = array();

foreach($formObj as $array){
    $myObj[$array["name"]] = $array["value"];
}

var_dump($myObj); // New object with key/value pair

answered Dec 13, 2017 at 15:39

William

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How can I transform a jquery object into a php array?

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