using sharex with odd number of subplots in matplotlib

Question

I have an odd number of subplots like so:

import matplotlib.pyplot as plt 

fig, axes = plt.subplots(2, 2, sharex=True)
for i, ax in enumerate(axes.flat):
    ax.plot(range(10))
fig.delaxes(axes.flat[-1])

I want them all to have the same x-axis, but easily add the x-ticks back to the plot on the right, since there is no longer a 4th plot.

It seems like there should be an easier/cleaner solution than adding each subplot manually (similar to this answer), but I can't seem to find anything. Thanks.

plasmon360 · Accepted Answer · 2017-12-14 22:15:58Z

2

you can use setp to make the xtick labels visible for ax[0][1] like this

import matplotlib.pyplot as plt 

fig, axes = plt.subplots(2, 2, sharex=True)
for i, ax in enumerate(axes.flat):
    ax.plot(range(10))
# for matploltib version 2.0.1
plt.setp(axes[0][1].get_xticklabels(), visible=True)
# for matplotlib version 2.1.1
axes[0][1].xaxis.set_tick_params(which='both', labelbottom=True, labeltop=False)
fig.delaxes(axes.flat[-1])
plt.show()

which will result in

edited Dec 14, 2017 at 22:15

answered Dec 13, 2017 at 20:17

plasmon360

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3 Comments

Leaf Over a year ago

what version of matplotlib are you using? I tried this with 2.1.0 and 2.1.1 (from conda-forge) and couldn't get this result (axes[0][1] still has no tick labels).

plasmon360 Over a year ago

see my latest edit. If the answer helped, please upvote/accept the answer. thanks!

Leaf Over a year ago

That worked, thanks! I upvoted the answer, but don't have enough reputation for it to show up :)

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