How to return new array from looping array indexes i and j

Question

Given an array of integers and I want to return indices of the two numbers such that they add up to a specific target. Assuming that each input would have exactly one solution, and I haven't used the same element twice.

I am using the brute force approach to Loop through each element x and find if there is another value that equals to target−x

code snippet:

var twoSum = function(nums, target) {
        for(var i ; i<nums.length ; i++){
            for(var j = i + 1; j<nums.length ; j++){
                if (nums[j]==target-nums[i]){
               // This is where I want to return new array 
                    return 
                    
                }
                
            }
        }
        
    };

for(var i ; isn't going to work, you need to initialise i with a number value: for(var i=0;, otherwise you're trying to do ++undefined. You haven't actually said what the problem is or any errors you get.++undefined produces NaN, then ++NaN continues to produce NaN so i<nums.length is always false (since NaN < anything is always false. — RobG
– RobG, Commented Dec 18, 2017 at 5:49

Robby Cornelissen · Accepted Answer · 2017-12-18 05:36:26Z

1

You just want to return the two indices?

return [i, j];

answered Dec 18, 2017 at 5:36

Robby Cornelissen

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3 Comments

Rajesh Dixit Over a year ago

May be its an opinionated comment, but I guess this could have been a comment

Philip Mutua Over a year ago

is it appropriate if I use new Array(i,j);

Charlie Martin Over a year ago

Always prefer array literals [] to using the constructor in javascript. Same goes with objects. Use {} instead of new Object()

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