I would like always click on the first link on Google using selenium robot for python. So for example if I write this :
driver.get("http://www.google.com")
elem = driver.find_element_by_name("q")
elem.send_keys("Tennis")
I would like to click on the first link that appears on Google
Thank you for your help !!
The accepted solution didn't work for me. So for anyone else that comes across that question driver.find_element_by_tag_name("cite").click() using python3 worked for me. However if you just want the link to the top search result it would be faster to use the requests and BeautifulSoup libraries as shown below
#!/usr/bin/env python3
import requests
from bs4 import BeautifulSoup
url = 'http://www.google.com/search?q=something'
page = requests.get(url)
soup = BeautifulSoup(page.text, "html.parser")
print(soup.find('cite').text)
The xpath which is working as of Aug 2019 is
(//h3)[1]/../../a
i.e. find the first h3 tag, move to its parents and find the first a.
driver.find_element(By.XPATH, '(//h3)[1]/../../a').click()
Google will surely change something in the future and then another approach will be needed.
Old answer
The results links all (used to have) have h3 as the parent element, you can use that
driver.find_element(By.XPATH, '(//h3)[1]/a').click()
span in your browser and build the xpath from that.