python finding and replacing list item if substring exist [duplicate]

Question

I want to replace the item in a list that contains a certain substring. In this case the item the contains "NSW" (capitals are important) in any form should be replaced by "NSW = 0". It doesn´t matter if the original entry reads "NSW = 500" or "NSW = 501". I can find the list item but somehow i can not find the postion in the list so i could replace it? This is what i came up with, but i replaces all items:

from __future__ import division, print_function, with_statement
my_list =["abc 123","acd 234","NSW = 500", "stuff","morestuff"]
for index, i in enumerate(my_list):
    if any("NSW" in s for s in my_list):
        print ("found")
        my_list[index]= "NSW = 0"
print (my_list)

If you are performing replacement by index, there's really no need for any. — cs95
– cs95, Commented Dec 20, 2017 at 12:11

Kaushik NP · Accepted Answer · 2017-12-20 12:12:51Z

3

Simple list comprehension:

>>> ["NSW = 0" if "NSW" in ele else ele for ele in l]

#driver values :

IN :    l = ["abc 123", "acd 234", "NSW = 500", "stuff", "morestuff"]
OUT : ['abc 123', 'acd 234', 'NSW = 0', 'stuff', 'morestuff']

answered Dec 20, 2017 at 12:12

Kaushik NP

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Jean-François Fabre · Accepted Answer · 2017-12-20 12:12:24Z

1

any won't give you the index and it will always be true at each iteration. So drop it...

Personally I'd use a list comprehension with a ternary to decide to keep the original data or replace by NSW = 0:

my_list =["abc 123","acd 234","NSW = 500", "stuff","morestuff"]

result = ["NSW = 0" if "NSW" in x else x for x in my_list]

result:

['abc 123', 'acd 234', 'NSW = 0', 'stuff', 'morestuff']

answered Dec 20, 2017 at 12:12

Jean-François Fabre♦

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1 Comment

NorrinRadd Over a year ago

I am sorry, i really didn´t find the linked thread

Mahesh Karia · Accepted Answer · 2017-12-20 12:15:38Z

1

Another solution: code:

from __future__ import division, print_function, with_statement
my_list =["abc 123","acd 234","NSW = 500", "stuff","morestuff"]
for index in xrange(len(my_list)):
    if "NSW" in my_list[index]:
        my_list[index] = "NSW = 0"

print (my_list)

output:

['abc 123', 'acd 234', 'NSW = 0', 'stuff', 'morestuff']

or you can use list comprehension for purpose as follows:

code:

my_list =["abc 123","acd 234","NSW = 500", "stuff","morestuff"]

print ["NSW = 0" if "NSW" in _ else _ for _ in my_list]

output:

['abc 123', 'acd 234', 'NSW = 0', 'stuff', 'morestuff']

answered Dec 20, 2017 at 12:15

Mahesh Karia

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