Let us Suppose, I have created 3 lists and I want to create a dictionary for it. e.g.
a= ['A', 'B', 'C', 'D']
b =[1, 2, 3, 4]
c = [9, 8, 7, 6]
Now What I want is to create a dictionary like this:
{'A':{'1' :'9'} , 'B':{'2':'8'}, 'C':{'3':'7'} , 'D':{'4':'6'}}
is it possible, Can Someone Help me on this?
You can create the dictionary from zip-ed lists and convert the int values to strings - if I understood your question proper
dct = {x: {str(y): str(z)} for x, y, z in zip(a,b,c)}
Output:
{'A': {'1': '9'}, 'C': {'3': '7'}, 'B': {'2': '8'}, 'D': {'4': '6'}}
You can also use map() here:
a = ['A', 'B', 'C', 'D']
b = [1, 2, 3, 4]
c = [9, 8, 7, 6]
dct = dict(map(lambda x, y, z : (x, {str(y): str(z)}), a, b, c))
print(dct)
Which outputs:
{'A': {'1': '9'}, 'B': {'2': '8'}, 'C': {'3': '7'}, 'D': {'4': '6'}}
dict(map(lambda)) is ugly. Use a dict comprehension instead like in atru's answer.
{ a[x]: {b[x]: c[x]} for x in range(len(a))}
or if you really mean it:
{ a[x]: {str(b[x]): str(c[x])} for x in range(len(a))}
a = ['A', 'B', 'C', 'D'] # don't forget the quotation marks
b = [1, 2, 3, 4]
c = [9, 8, 7, 6]
res = dict()
for i, index_a in enumerate(a):
res[index_a] = {str(b[i]): c[i]}
Edit: Alternatively with list comprehension (mainly for the voters in here, as it's advanced python and harder to understand):
res = dict((a[i], {str(b[i]): c[i]}) for i in range(len(a)))
{a[i]: {str(b[i]): c[i]} for i in range(len(a))}.You can try this:
a= ['A', 'B', 'C', 'D']
b =[1, 2, 3, 4]
c = [9, 8, 7, 6]
new_data = dict([[a, dict([map(str, i)])] for a, i in zip(a, zip(b, c))])
Output:
{'A': {'1': '9'}, 'C': {'3': '7'}, 'B': {'2': '8'}, 'D': {'4': '6'}}
Or
new_data = dict(zip(a, map(lambda x:dict([x]), zip(map(str, b), map(str, c)))))
dict can take a generator expression: dict([a, dict([map(str, i)])] for a, i in zip(a, zip(b, c)))Assuming what you want is to have a be keys in the outer dictionary, and b and c the key and value element of the inner dicts:
d = {k: {x: y} for k, x, y in zip(a, b, c)}
Update:
However, in your example x and y are strings, so if that's what you want:
d = {k: {str(x): str(y)} for k, x, y in zip(a, b, c)}
Are you looking for something like this ?
a= ['A', 'B', 'C', 'D']
b =[1, 2, 3, 4]
c = [9, 8, 7, 6]
new_dict={}
set(map(lambda x,y,z:(new_dict.__setitem__(x,{y,z})),a,b,c))
print(new_dict)
output:
{'D': {4, 6}, 'A': {9, 1}, 'B': {8, 2}, 'C': {3, 7}}
set(map(lambda)) is ugly. 4) OP wants dicts inside, not sets. So: new_dict = {}; for x, y, z in zip(a, b, c): new_dict[x] = {y: z}, which you can boil down into a comprehension, like in atru's answer: new_dict = {x: {y: z} for x, y, z in zip(a, b, c)}