How can a turn this code into a shorthand line of code? is it possible at all?
I would like the same purpose of the code, but with the least amount of lines possible
inpt = input('Age: ')
age = int(inpt)
if age <= 10:
print('Kid')
elif age > 10 <= 20:
print('Teen')
elif age > 20:
print('Adult')
Let's try:
text = 'kid' if age <= 10 else 'teen' if age <= 20 else 'adult'
Example:
age = 4
text = 'kid' if age <= 10 else 'teen' if age <= 20 else 'adult'
print(text)
age = 12
text = 'kid' if age <= 10 else 'teen' if age <= 20 else 'adult'
print(text)
age = 25
text = 'kid' if age <= 10 else 'teen' if age <= 20 else 'adult'
print(text)
Output:
kid
teen
adult
It's possible to shorten it to:
age = int(input('Age: '))
print('Kid' if age <= 10 else 'Teen' if age <= 20 else 'Adult')
That said, unless you're doing one-liners for fun, I'd stick to your original code, after fixing the test for Teen and just making the Adult case a plain else (no need to retest > 20 since the previous cases eliminated the other possibilities).
This may not be that suggested but you can try out something using short circuiting. I personally think this is more readable(not for your example) but at the cost of extra comparisons.
input = input('Age: ')
age = int(input)
age <= 10 and print('Kid')
age > 10 and age <= 20 and print('Teen')
age > 20 and print('Adult')
What about:
age = int(input('Age: '))
print('Adult' if age > 20 else 'Kid' if age <= 10 else 'Teen')
In Python you have a ternary operator:
a if condition else b
age >10 <=20doesn't do what you think. It expands to the equivalent ofage > 10 and 10 <= 20. Which means yourAdultcase is never reached, you only printKidorTeen. You want10 < age <= 20.