jQuery syntax for using with variables

Question

jQuery not working with variable. the issue is with this line:

$('img[alt = id]').trigger("click");

if I change it to

$('img[alt = "6"]').trigger("click");

Everything works as expected. I just can't workout how to use a variable instead of a value within the quotes. I have tried putting id in single / double quotes with no luck. I'm sure it will be something obvious. Can anyone help.

This is the full code.

$(window).load(function () {
        // run code
       // $('img[alt ="6"]').trigger("click");
        var id = localStorage.getItem("CustomerID");
        $('img[alt = id]').trigger("click");
      //  window.alert(id);
    });

Tallboy · Accepted Answer · 2017-12-24 00:56:58Z

3

You can combine a string and use that instead:

$('img[alt = "' + 6 + '"]').trigger("click");

Here it is as a variable:

var id = 6;
$('img[alt = "' + id + '"]').trigger("click");

It's called string concatenation.

answered Dec 24, 2017 at 0:56

Tallboy

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2 Comments

SANM2009 Over a year ago

Thanks mate. So simple when you know how. I will accept your answer once I can in few minutes.

SANM2009 Over a year ago

I actually tried something similar. $('img[alt = ' + id + ']').trigger("click"); But I user it without the double quotes, I didn't realise they are needed as part of the statement.

David Thomas · Accepted Answer · 2017-12-24 01:01:30Z

1

Watch this

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Template_literals

Example:

$(`img[alt = "${id}"]`).trigger("click");

edited Dec 24, 2017 at 1:01

David Thomas

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answered Dec 24, 2017 at 0:59

False

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