BASH-SHELL SCRIPT: Print part of the text from a file

Question

So i have a text file with part of html code:

>>nano wynik.txt

with text:

1743: < a href="/currencies/lisk/#markets" class="price" data-usd="24.6933" data-btc= "0.00146882"

and i want to print only: 24.6933

I tried the way with the cut command but it does not work. Can anyone give me a solution?

What is the criteria for a number getting printed? Are you only worried about data-usd? — Thomas Smyth
– Thomas Smyth, Commented Jan 6, 2018 at 0:41
I suggest to use an XML/HTML parser (xmlstarlet, xmllint ...). — Cyrus
– Cyrus, Commented Jan 6, 2018 at 0:42
@ThomasSmyth result.txt is only a temporary file which is deleted at the end of the script, its content depends on what data I download from the website although the text pattern is always the same but the data-usd value is different, for example: 12.1594 or 1203.394, so the text length also it's different. I only need the data-usd value that I can capture into a variable or edit the file result.txt so that only this value is there. I hope you understand the message :). — Salim Azeri
– Salim Azeri, Commented Jan 6, 2018 at 0:50
Does the file really have 1743: at the beginning of the line? So it's not really HTML, it has extra formatting added? — Barmar
– Barmar, Commented Jan 6, 2018 at 0:53

Cyrus · Accepted Answer · 2018-01-06 00:46:04Z

2

grep -Po '(?<=data-usd=").*?(?=")' file

Output:

24.6933

answered Jan 6, 2018 at 0:46

Cyrus

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