Can't access parent attribute in inherited Python class

Question

This is my parent class,

class BaseResource:
    def __init__(self):
        self.logger = logging.getLogger(__name__)
        fmt = '[%(asctime)s] [%(levelname)s] [%(message)s] [--> %(pathname)s [%(process)d]:]'
        logging.basicConfig(format=fmt, level=logging.DEBUG)

    def log(self, msg):
        self.logger.debug(msg)

This is my inherited object,

class SendOTP(BaseResource):

    def __init__(self):
        super(BaseResource, self).__init__()

    def on_post(self, req, res):
        self.logger.log("[FAILURE]..unable to read from POST data")

This throws up the following error,

AttributeError: 'SendOTP' object has no attribute 'logger'

What am I doing wrong here.

If this is python3, you could simplify the super call to super().__init__() — cs95
– cs95, Commented Jan 6, 2018 at 17:22

user2357112 · Accepted Answer · 2018-01-06 17:22:11Z

7

It should be super(SendOTP, self), not super(BaseResource, self).

Also, if this is Python 3, you can simplify it to just super(); if Python 2, you also need to change the declaration of BaseResource to

class BaseResource(object):

to get a new-style class.

answered Jan 6, 2018 at 17:22

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user2357112

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4 Comments

Melissa Stewart Over a year ago

This worked but just curious, class BaseResource(object) is the old Python 2 style, right?

Melissa Stewart Over a year ago

But now I get the following error, TypeError: log() missing 1 required positional argument: 'msg'

Melissa Stewart Over a year ago

So I guess this is an additional question, I'm trying to call a method from the super and I'm passing in the correct argument and still getting an error.

user2357112 Over a year ago

@MelissaStewart: Read the docs for Logger.log.

Vasyl Lyashkevych · Accepted Answer · 2018-01-06 18:36:10Z

2

If it is python 3 you have to use: Super()._init_()

instead of super(BaseResource, self).__init__()

and

super().log("[FAILURE]..unable to read")

instead of self.logger.log("[FAILURE]..unable to read")

If it is python 2 you have to use: BaseResource.__init__(self)

instead of super(BaseResource, self).__init__()

and

self.log("[FAILURE]..unable to read")

instead of self.logger.log("[FAILURE]..unable to read")

edited Jan 6, 2018 at 18:36

Vasyl Lyashkevych

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answered Jan 6, 2018 at 17:45

Humza Jalal

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Comments

Ran S · Accepted Answer · 2018-01-06 17:36:25Z

1

In super you should put your class type

>>> class A(object):
...     def __init__(self):
...             print("hi")

>>> class B(A):
...     def __init__(self):
...             super(B, self).__init__()

>>> class C(A):
...     def __init__(self):
...             super(A, self).__init__()

>>> B()
hi
<__main__.B object at 0x0000024F90141C88>

>>> C()
<__main__.C object at 0x0000024F90141D30>

answered Jan 6, 2018 at 17:36

Ran S

11510 bronze badges

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