using requests module to access api

Question

The curl command works as expected. But similar python code does not.

# curl -X POST -H "Content-Type: application/json" -d '{"img_url":"http://tleyden-misc.s3.amazonaws.com/blog_images/ocr_test.pnge","engine":"tesseract"}' http://35.154.148.131:9292/ocr

Expected output:

You can create local variables for the pipelines within the template by
prefixing the variable name with a "$" sign. Variable names have to be
composed of alphanumeric characters and the underscore. In the example
below I have used a few variations that work for variable names.

I tried this python code:

import requests
url = 'http://35.154.148.131:9292'
data = {"img_url":"http://tleyden-misc.s3.amazonaws.com/blog_images/ocr_test.png","engine":"tesseract"}  
r = requests.post( url, json={'json_payload': data})

This returns the following error:

b'<h1>OpenOCR is running!<h1> Need <a href="http://www.openocr.net">docs</a>?'

How do I post the dictionary using data parameter?

How about calling just r = requests.post( url, json=data)? According to documentation that's the way to use it. Also, in your Python code, you are missing the /ocr endpoint in the URL. — Tomáš Linhart
– Tomáš Linhart, Commented Jan 8, 2018 at 9:15

shantanuo · Accepted Answer · 2018-01-08 09:10:53Z

2

This is how I managed to do this:

import requests
url = 'http://35.154.148.131:9292/ocr'
data = {"img_url":"http://tleyden-misc.s3.amazonaws.com/blog_images/ocr_test.png","engine":"tesseract"}  

r = requests.post( url, json=data )

answered Jan 8, 2018 at 9:10

shantanuo

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Comments

dorvak · Accepted Answer · 2018-01-08 10:00:14Z

1

import requests 
url = 'http://35.154.148.131:9292/ocr'
data = {"img_url":"http://tleyden-misc.s3.amazonaws.com/blog_images/ocr_test.png","engine":"tesseract"}
r = requests.get(url, json=data) 
r.text

Result

u'You can create local variables for the pipelines within the template by\nprefixing the variable name with a "$" sign. Variable names have to be\ncomposed of alphanumeric characters and the underscore. In the example\nbelow I have used a few variations that work for variable names.\n\n'

edited Jan 8, 2018 at 10:00

dorvak

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answered Jan 8, 2018 at 9:17

Jishnunand P K

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