PHP json string variable

Question

I want to decode a JSON string. However, the value that I got is something like this string(100) "{"data":{"type":"campaign-folders","id":"d208f3171a","attributes":{"name":"My Folder"}}}".

Could anyone tell me what should I do so that I can treat this variable as a usual string ?

“However, the value that I got is something like this” - that looks like the output var_dump creates - but in that case, it of course does not mean that this is the actual content of your string variable. string(100) is additional “meta data” var_dump provides you with (type & length.) — C3roe
– C3roe, Commented Jan 10, 2018 at 10:38

Dylan Delobel · Accepted Answer · 2018-01-10 10:27:54Z

1

Use json_decode http://php.net/manual/en/function.json-decode.php

$obj = json_decode($json);
var_dump($obj);

answered Jan 10, 2018 at 10:27

Dylan Delobel

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Rafi Ramadhan Over a year ago

Thanks, it's work. I think I should treat the string differently, but it's just the same

Boni · Accepted Answer · 2018-01-10 10:31:47Z

0

Use json_decode ,you can solve it.

var_dump(json_decode($json, true));//check this.

answered Jan 10, 2018 at 10:31

Boni

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Comments

Nimesh Patel · Accepted Answer · 2018-01-10 11:40:16Z

0

here to convert JSON string to Array

 $someArray = json_decode($someJSON, true);
  print_r($someArray);
 echo $someArray[0]["name"];

and here to convert JSON to Object

$someObject = json_decode($someJSON);
 print_r($someObject);
 echo $someObject[0]->name;

edited Jan 10, 2018 at 11:40

Nimesh Patel

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answered Jan 10, 2018 at 10:44

sancoLgates

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