How to use Button click to open url from JSON feed?

Question

I'm fetching JSON feed using Volley, which contains Name, Rating and URL. I have textview on Android which will display Fetched Name, Rating and all. I have a Button but it's showing the URL directly because I set Text as Fetched URL.

Currently, I'm getting this:

I need to Set Text of Button as Register & If the Button is clicked it should open the URL Fetched from the JSON Feed.

Hereby I'm attaching the code

    @Override
    public void onBindViewHolder(CourseViewHolder holder, int position) {

        Course course = courseList.get(position);

        holder.textViewCoursename.setText(course.getCoursename());
        holder.textViewcoursedescshort.setText(course.getCoursedescshort());
        //holder.textViewcourseurl.setText(course.getCourseurl());
        holder.textViewcourserating.setText(course.getCourserating());

        Glide.with(mCtx)
                .load(course.getCourseimg())
                .into(holder.imageView);

        Button button = (Button) button.findViewById(R.id.textViewcourseurl);
        button.setOnClickListener(new Button.OnClickListener() {
            public void onClick(View v) {
                //Do stuff here
            }
        });
    }

will you open url in a browser or webview ?

Umair
– Umair

2018-01-15 07:28:03 +00:00
Commented Jan 15, 2018 at 7:28 — Umair
– Umair, Commented Jan 15, 2018 at 7:28
I'm trying to open in Browser Buddy :)

MC Naveen
– MC Naveen

2018-01-15 07:35:49 +00:00
Commented Jan 15, 2018 at 7:35 — MC Naveen
– MC Naveen, Commented Jan 15, 2018 at 7:35
I have answered the question please check :)

Umair
– Umair

2018-01-15 07:40:00 +00:00
Commented Jan 15, 2018 at 7:40 — Umair
– Umair, Commented Jan 15, 2018 at 7:40

Valentin Michalak · Accepted Answer · 2018-01-15 21:09:41Z

1

You can use Intent for this task.

//Just put Intent on your button click
button.setOnClickListener(new Button.OnClickListener() {
    public void onClick(View v) {
        Intent i = new Intent(Intent.ACTION_VIEW);
        i.setData(Uri.parse(course.getCourseurl()));
        mCtx.startActivity(i);
        //This will open url in browser if you have application in your device.
    }
});

If you want to load url in WebView than check below link

How to load external webpage inside WebView

edited Jan 15, 2018 at 21:09

Valentin Michalak

2,1471 gold badge16 silver badges27 bronze badges

answered Jan 15, 2018 at 7:31

Lokesh Desai

2,67719 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

7 Comments

MC Naveen Over a year ago

In which file I have to use this?

Lokesh Desai Over a year ago

@MCNaveen in adapter u have already made click listener for button

MC Naveen Over a year ago

Tried Replacing my Code with yours.. Now I'm getting the Following Error... Error:(64, 17) error: method startActivity in class ContextCompat cannot be applied to given types; required: Context,Intent,Bundle found: Intent reason: actual and formal argument lists differ in length

MC Naveen Over a year ago

Build and Installation successful, But the App keeps crashing after opening. Here is the Logcat : pastebin.com/naAvZ7Z8

Lokesh Desai Over a year ago

@MCNaveen Button button = (Button) button.findViewById(R.id.textViewcourseurl); this code in your Adapter's ViewHolder as you have done findviewbyid for TextViews. Than use like holder.btn.setOnCliccklistner...

|

Salaudeen Abdulrahman · Accepted Answer · 2018-01-15 07:43:50Z

0

I need to Set Text of Button as Register & If the Button is clicked it should open the URL Fetched from the JSON Feed

You should load the URL with Intent specifying an action. For example to load the URL:

String url = //get your url from the JSON feed ;

Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);

Basically, the code above will do the work of finding apps that can load the URL and loading the URL for you.

Do not forget to check if the URL is empty before you pass it to an intent

answered Jan 15, 2018 at 7:43

Salaudeen Abdulrahman

1293 bronze badges

Comments

Ergin Ersoy · Accepted Answer · 2018-01-15 07:45:54Z

0

In your adapter where you have declared button, you need to implement onClick method of button:

Button button = (Button) button.findViewById(R.id.textViewcourseurl);
button.setOnClickListener(new Button.OnClickListener() {
    public void onClick(View v) {
        Uri uri = Uri.parse("http://www.google.com"); 
        Intent intent = new Intent(Intent.ACTION_VIEW, uri);
        context.startActivity(intent);
    }
});

This will help you open the specific url in your available browsers. And if you want to open your url in webview, follow this link. How to open a url in webview on new screen based on button click

edited Jan 15, 2018 at 7:45

Ergin Ersoy

8898 silver badges28 bronze badges

answered Jan 15, 2018 at 7:33

Umair

6,42616 gold badges44 silver badges50 bronze badges

Comments

Muhammed Refaat · Accepted Answer · 2018-01-15 08:36:46Z

0

inside your adapter onBindViewHolder() method, it would be like that:

// get the course url
String courserURL = course.getCourseurl();
button.setOnClickListener(new Button.OnClickListener() {
     public void onClick(View v) {
         // make sure the course url value is not empty
         if(!courserURL.isEmpty()){
             // assign an ActionView to run that URL
             Intent i = new Intent(Intent.ACTION_VIEW);
             i.setData(Uri.parse(courserURL));
             holder.button.getContext().startActivity(i);
         }
     }
 });

edited Jan 15, 2018 at 8:36

answered Jan 15, 2018 at 7:44

Muhammed Refaat

9,16315 gold badges92 silver badges126 bronze badges

2 Comments

MC Naveen Over a year ago

Returns an error

Error:(69, 21) error: method startActivity in class ContextCompat cannot be applied to given types; required: Context,Intent,Bundle found: Intent reason: actual and formal argument lists differ in length

Muhammed Refaat Over a year ago

@MCNaveen sure it would, as you have to startActivity using the context, try my updated answer, also you can have a look here stackoverflow.com/a/32137097/1638739

Ergin Ersoy · Accepted Answer · 2018-01-15 08:47:46Z

0

To change bottom name, you need to use ArrayList<String> to open link of bottom:

Intent browserIntent = new Intent(Intent.ACTION_VIEW);
browserIntent.setData("YourLinkHere);
context.startActivity(browserIntent);

edited Jan 15, 2018 at 8:47

Ergin Ersoy

8898 silver badges28 bronze badges

answered Jan 15, 2018 at 8:13

Amin Nemati

1067 bronze badges

Collectives™ on Stack Overflow

How to use Button click to open url from JSON feed?

5 Answers 5

7 Comments

Comments

Comments

2 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

7 Comments

Comments

Comments

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related