openpyxl write multiple rows in Excel

Question

I am trying to write multiple rows to Excel. "Containers" has an index/len of 10. Although I loop through it, I only get one row when I run the script.

Can anyone help me with this?

# define first empty row
start_row = sheet.max_row + 1

#write to excel
for container in containers:
 #Company name
 company_container = container.div.h2
 company = company_container.text.strip()

 #City
 city = container.div.a["title"]

 #URL
 url = container.div.div.a["href"]

 #Title
 title_container = container.findAll("div", {"class":"info"})
 title = title_container[0].img["alt"]

 #Description
 description = title_container[0].p.text

 #Programming language
 hardskill = "Java"

 #Vervolgactie (Teamleader)
 vervolgactie = "Nieuw"

 companyinfo = [company, city, url, title, description, hardskill, vervolgactie]

 for i in range(0,len(companyinfo)):
   e=sheet.cell(row=start_row,column=1+i)
   e.value=companyinfo[i]

wb.save("vacatures.xlsx")

Taylor Francis · Accepted Answer · 2018-01-24 19:54:38Z

1

Your problem is that you're writing everything out with e=sheet.cell(row=start_row,column=1+i) on the same row.

since everything in enclosed in the loop for container in containers, i'd just increment start_rowafter the sub loop.

 for i in range(0,len(companyinfo)):
   e=sheet.cell(row=start_row,column=1+i)
   e.value=companyinfo[i]

 start_row +=1 #not part of the above loop but part of the overarching loop

Another route i'd consider is to rename start_row to just row (this is more semantically clear) and have row defined in the loop

#start_row = sheet.max_row + 1

#write to excel
for container in containers:
 #row for this data to go on. 
 row = sheet.max_row + 1

 #Company name
 company_container = container.div.h2
 company = company_container.text.strip()

answered Jan 24, 2018 at 19:54

Taylor Francis

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