Failed loop: asking the user if they wish to continue (Python)

Question

I developed this code for Python 3 in order to ask the user if they wish to continue:

def dnv(): 
    b = input('Would you like to try again? Type 1 for "yes" and 0 for "no": ')
    if b == '1':
        return run()
    if b == '0':
        return print('See you later!')

run() is any program's main function. But now I'm taking a course on Python 2 and I've tried to adapt it on an algorithm I took from there, with no success. The objetive was to determine how many days are between two dates. I believe the relevant part is:

def inputs():
    year1 = input('Type the first year: ')
    month1 = input('Type the first month: ')
    day1 = input('Type the first day: ')
    year2 = input('Type the second year: ')
    month2 = input('Type the second month: ')
    day2 = input('Type the second day: ')
    print daysBetweenDates(year1, month1, day1, year2, month2, day2)

def dnv():
    answer = input('Would you like to try again? Type "y" for yes and "n" for no: ')
    if answer == 'y':
        return inputs()
    else:
        print('See you later!')

I get a NameError: name 'y' is not defined (analogue to 'n') though everytime I type y or n. I've also tried to modify if answer == 'y' to:

if answer.lower().startswith('y'):
    return inputs()

Again with no success. What am I missing? Thank you!

python2 input() works differently from python3 input(). Try raw_input() instead. — Zinki
– Zinki, Commented Jan 20, 2018 at 16:49

user3773246 · Accepted Answer · 2018-01-20 16:51:32Z

2

Use raw_input()

answer = input('Would you like to try again? Type "y" for yes and "n" for no: ')

answered Jan 20, 2018 at 16:51

user3773246

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Comments

user8982390 · Accepted Answer · 2018-01-20 16:58:38Z

1

If you are using the python 2 you need to change the input to:

answer = raw_input("your message here: ")

And you don't need to return a function you can just call it.

if answer.lower().startswith('y'):
    inputs()

answered Jan 20, 2018 at 16:58

user8982390

Comments

JasonG · Accepted Answer · 2018-01-20 17:23:33Z

1

if you are using python 3, I recommend this:

b = input('Would you like to try again? Type 1 for "yes" and 0 for "no": ')
   if b == '1':
       return run()
   if b == '0':
       return print('See you later!')

answered Jan 20, 2018 at 17:23

JasonG

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