Extract Function name from Notepad++ for FunctionList

Question

I am trying to set up a Function List for a new language in Notepad++. To do so, it requires me to add a parser in functionlist.xml. I added the parser, and it works, but it also adds the actual word function in the function list. How can I remove word function from it? I have looked into the Regular Expression's lookbehind feature. But I could not make it work.

Here is the parser.

<parser displayName="mylang" id="mylang_syntax">
  <function mainExpr="^\s*(function|Function|FUNCTION)[\t ]+[\w]+">
    <functionName>
      <NameExpr expr="/(?<=^function /)[\w]+" />
      <NameExpr expr="/(?<=^Function /)[\w]+" />
      <nameexpr expr="/(?<=^FUNCTION /)[\w]+" />
    </functionName>
  </function>
</parser>

Here is an example text to try on.

FUNCTION uniqn, input_array
  IF(!DEBUG) THEN PRINT, 'uniqn_no_sort'
  counter = 0L
  length = n_elements(input_array(*, 0))
  duplicate_array = STRARR(length)
END

function get_algorithm_type, type
  IF(!DEBUG) THEN PRINT, 'get_algorithm_type'
  print, type
END

This is how it looks in the functionlist sidebar. I would like to remove the word 'function'. Please note that it needs to work in Notepad++. (I cannot use any other Text editors). Thank you in advance for your help.

Here are additional help.

Gurmanjot Singh · Accepted Answer · 2018-01-24 14:23:27Z

2

Try the Regex below:

(?i)(?<=^function)\s+\K\w+

Click for Regex Demo

Regex Explanation:

(?i) - modifier to make the search case-insensitive
(?<=^function) - positive lookbehind to find the position immediately preceded by the sub-string function at the start of the line
\s+ - matches 1+ occurrences of a white-space character
\K - forget everything matched so far
\w+ - matches 1+ occurrences of all the characters which fall within the character class [a-zA-Z0-9_]

Add the following parser tag to the file functionList.xml

<parser id="mylang" displayName="mylang_syntax">
    <function mainExpr="(?i)(?<=^function)\s+\K\w+" />
</parser>

OUTPUT

As you can see below, extra spaces between the function and the functionName have also been ignored

edited Jan 24, 2018 at 14:23

answered Jan 24, 2018 at 14:04

Gurmanjot Singh

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4 Comments

DigitalNomad Over a year ago

Thank you so much @Gurman. It works great. \K was awesome. I did not know such feature existed. I have one more small request. Is it possible to add another type of function, which actually start with pro. pro another_routine, type IF(!DEBUG) THEN PRINT, 'get_algorithm_type' print, type END

Gurmanjot Singh Over a year ago

@Cricrazy For that case, you can use this regex (?i)(?:(?<=^function)|(?<=^pro))\s+\K\w+

Gurmanjot Singh Over a year ago

@Cricrazy Also, If the answer helped you, please consider upvoting it or accepting the answer

DigitalNomad Over a year ago

works perfectly. Accepted as the answer most gladly. Thank you very much.

Gurmanjot Singh · Accepted Answer · 2018-01-24 14:43:21Z

1

Try it like this

<parser displayName="mylang" id="mylang_syntax">
  <function mainExpr="(?<=function|Function|FUNCTION)[\t ]+[\w]+"/>
</parser>

and you get

edited Jan 24, 2018 at 14:43

Gurmanjot Singh

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answered Jan 24, 2018 at 2:29

wp78de

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