Exception Handling In Android from Web API

Question

My code in MVC API C# this:

    [System.Web.Http.HttpPost]
    [System.Web.Http.Route("api/ServiceV1/Test")]
    public IHttpActionResult Test()
    {
        return BadRequest("Catch this message in Android application");
    }

Result in PostMan

{
    "Message": "Catch this message in Android application"
}

I catch this error message on android application. I used okhttp3.

    String MIME_JSON = "application/json";
    Gson gson = new Gson();
    RequestBody body = RequestBody.create(MediaType.parse(MIME_JSON), gson.toJson(object));

    Request request = new Request.Builder()
            .url(baseUrl + route)
            .post(body)
            .build();

    okHttpClient.newCall(request).execute();

How do to catch this message on the Android application?

Mor A. · Accepted Answer · 2018-01-28 08:07:01Z

1

the Call.execute() method returns a Response object, which has the code() method to find the status code, and the isSuccessful() method to find whether the code is in the [200,300) range, which generally represent success.

Generally looking at the documentation of libraries you are working with is helpful. Here's the documentation for okhttp

answered Jan 28, 2018 at 8:07

Mor A.

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Comments

Ahmad Aghazadeh · Accepted Answer · 2018-01-30 05:49:29Z

0

Can read this error:

Response response=okHttpClient.newCall(request).execute();
if (response.code() != 200) {
  errorMessage= response.body().string();
}

answered Jan 30, 2018 at 5:49

Ahmad Aghazadeh

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