Create an array of Tuple depending on an array of data in C#

Question

Suppose I have this data int[] a = [1,2,3,4,5]

I would like to create Tuple<int,int,bool>[] where the first element is itself, the second is it's double value and the last element is whether it is an even number or not.

That is, the resulting data would be :

(1, 2, false)
(2, 4, true)
(3, 6, false)
(4, 8, true)
(5, 10, false)

One solution I have is to create a list, make a for loop over a array and new each Tuple, add to the list, and then finally use .ToArray on the list. But I think there must be an elegant way to do this. I don't mind using LINQ.

    int[] a = [1, 2, 3, 4, 5];
    List<Tuple<int,int,bool>> list = new List<Tuple<int, int, bool>>();
    {
        foreach(int i in a)
        {
            list.Add(new Tuple<int, int, bool>(i, i * 2, i % 2 == 0));
        }
    }
    return list.ToArray();

I suggest moving this question to codereview.stackexchange.com — rattrapper
– rattrapper, Commented Feb 1, 2018 at 12:24

Zohar Peled · Accepted Answer · 2018-02-01 12:24:47Z

4

A simple Select should do the trick:

var tuples  = a.Select(v => Tuple.Create(v, v * 2, v % 2 == 0)).ToArray();

answered Feb 1, 2018 at 12:24

Zohar Peled

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Comments

cpr43 · Accepted Answer · 2018-02-01 12:26:42Z

1

Using a select query would solve the problem.

int[] a = [1, 2, 3, 4, 5];
var result =  a.Select(x => Tuple.Create<int, int, bool>(x, 2 * x, x % 2 == 0)).ToArray();

answered Feb 1, 2018 at 12:26

cpr43

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2 Comments

cpr43 Over a year ago

oh .. he got it first :(

Zohar Peled Over a year ago

@CamiloTerevinto in my answer it's v, not x, and also v * 2 and not 2 * x. Don't be too hard on the guy, sometimes you don't get the updates in time...

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