Create multiple buttons with sub windows in Tkinter Python

Question

I have Accountid column in a Dataframe. Now I am using Tkinter to draw some gui. For each Accountid I want to create a separate button.My code is able to do that. But after this, for each button I want to create a subwindow, which would contain some columns for each Accountid. Now the problem is that my code creates sub-window for each button, but it fetches the columns for only the last Accountid.

I would really appreciate if someone can help me.

import tkinter as tk

class Example(tk.Frame):
    def __init__(self, parent):

        tk.Frame.__init__(self, parent)
        for id in df['AccountId']:##for each id create a button

            new_win_button = tk.Button(self, text=id, 
                                   command= self.new_window)
            new_win_button.pack(side="top", padx=20, pady=20)


    def new_window(self):

        top = tk.Toplevel(self)# create sub window
        print (id)
        #print (id is 'id')
        label = tk.Label(top, text=s3.loc[s3.AccountId == id][['AccountId','confidence','lift']])

        label.pack(side="top", fill="both", expand=True, padx=20, pady=20)


if __name__ == "__main__":
    root = tk.Tk()
    Example(root).pack(fill="both", expand=True)
    root.mainloop()

Pratik Kumar · Accepted Answer · 2018-02-15 11:36:19Z

1

After this loop :

for id in df['AccountId']:##for each id create a button

            new_win_button = tk.Button(self, text=id, 
                                   command= self.new_window)
            new_win_button.pack(side="top", padx=20, pady=20)

id is a local variable to the class Example. And id is set to the last value of df['AccountId'] at the end of the above for loop. for example:

for i in range(0,10):
  pass
print i

Result:

9

So in

label = tk.Label(top, text=s3.loc[s3.AccountId == id][['AccountId','confidence','lift']])

the comparison s3.AccountId == id will always comapare with the latest value of id that's why you are always getting the columns for only the last Accountid.

workaround :

import tkinter as tk
import pandas as pd

root = tk.Tk() #declare root in global scope for simplicity


class new_button:

    def __init__(self,A_id):

        self.id=A_id
        but = tk.Button(root,text=self.id,command=self.new_window)
        but.pack(side="top", padx=20, pady=20)



    def new_window(self):

        top = tk.Toplevel(root)# create sub window

        label = tk.Label(top, text=s3.loc[s3.AccountId == self.id][['AccountId','confidence','lift']])

        label.pack(side="top", fill="both", expand=True, padx=20, pady=20)


if __name__ == "__main__":
    for i in df['AccountId']:##for each id create a button

            butt=new_button(A_id=i)

    root.mainloop()

created a new_button class which creates a unique button for each AccountId in the dataframe.

edited Feb 15, 2018 at 11:36

answered Feb 14, 2018 at 7:32

Pratik Kumar

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2 Comments

user2906657 Over a year ago

Thanks for the detailed response. But how to resolve this? Any suggestions.

Pratik Kumar Over a year ago

@user2906657, provide a sample for df and s3

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