Getting file paths outside the folder

Question

I want to acces files outside my main.js folder,below is my folder structure:

ent
 src
   ep
    main.js
 config
   abc.js
   xyz.js

I have tried doing var config_src = __dirname+"/../../config" it works fine, but not acceptable bt my TL.What is the other way to get the path of congig folder?

Can you explain what a TL is?

devius
– devius

2018-02-16 13:06:58 +00:00
Commented Feb 16, 2018 at 13:06 — devius
– devius, Commented Feb 16, 2018 at 13:06

Pushpendra Kumar · Accepted Answer · 2018-02-16 13:02:33Z

5

__dirname returns your working (project) directory. then you have out from that folder. suppose your folder structure and using sonfig_src in app.js :

somefoledr
   |___somefolder1
   |___somefolder2
          |__config
yourProject
   |___ app.js

One more thing you did not used const path = require('path') package.

Now your code should look like this :

const path = require('path')
const config_src = path.resolve(__dirname, "/../somefoledr/somefoledr2/config")

But it can be harmful when you will deploy it on server, it could create path problem !

edited Feb 16, 2018 at 13:02

answered Feb 16, 2018 at 12:56

Pushpendra Kumar

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5 Comments

tintin Over a year ago

I want to completely remeove the usage of "../" and fetch the absolute path of config folder

tintin Over a year ago

I tried a lot but using varoius ways, bt could get path till the src folder, how can i fetch the path for config without usage of "../"

Pushpendra Kumar Over a year ago

checkout this link, m sure you will find you solution here : nodejs.org/api/path.html

tintin Over a year ago

but setting path this way will not work when the project is deployed. The path may not be the sane

tintin Over a year ago

I tried using require('app-root-path') which gives me the path till src directory, but again am stuck how to navigate till config.I dont want to use "../" for that purpose

kingdaro · Accepted Answer · 2018-02-16 13:06:59Z

1

Use path.resolve

const path = require('path')
const config_src = path.resolve(__dirname, "../../config")

edited Feb 16, 2018 at 13:06

answered Feb 16, 2018 at 12:50

kingdaro

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