sending parameters with json in swift

Question

I'm trying to use webapi in my code. my JSON service has odata filtering. But when I try to send my link into my JSON serializer, I get "nil" response at myURL2. But if I send without parameter it works fine. Do you have any suggestions? How can I use ODATA in my code?

        let link = "https://apiservices.domain.com/api/Events?$filter=EventDate gt datetime'2018-02-01' and EventDate lt datetime'2018-02-15'"

        let myURL2 = NSURL(string: link)
        let request2 = NSMutableURLRequest(url: myURL2 as! URL)
        request2.httpMethod = "GET"


        request2.addValue("Bearer "+tokenNewId, forHTTPHeaderField: "Authorization")
        request2.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "content-type")
        request2.setValue("application/json", forHTTPHeaderField: "Accept")

        let task2 = URLSession.shared.dataTask(with: request2 as URLRequest) {(data2, response2, error2) -> Void in
            if let unwrappedData2 = data2 {
                do {
                    guard let records = try? JSONSerialization.jsonObject(with: unwrappedData2, options: .mutableContainers) as? [[String: Any]] else {
                        return
                    }
           }

...$filter=EventDate gt datetime'2... The spaces may cause the issue. Could you check url then? — Larme
– Larme, Commented Feb 23, 2018 at 13:04
My bad, wasn't explicit, could you check the value of myURL2 then? — Larme
– Larme, Commented Feb 23, 2018 at 13:10
Postman must percent-escape the URL before sending it. Spaces are most definitely not legal in URLs. — Duncan C
– Duncan C, Commented Feb 23, 2018 at 13:33

Ahmad F · Accepted Answer · 2018-02-23 13:48:15Z

1

Try this:

let urlwithPercentEscapes = link.addingPercentEncoding( 
withAllowedCharacters: .urlQueryAllowed)
let myURL2 = NSURL(string: urlwithPercentEscapes!)

edited Feb 23, 2018 at 13:48

Ahmad F

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answered Feb 23, 2018 at 13:20

Darkface35

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1 Comment

Duncan C Over a year ago

Spaces are not legal in URLs. Since your URL contains spaces, each space character must be escaped as %20. That's what this answer does, and why it work.

Enrique Bermúdez · Accepted Answer · 2018-02-23 13:09:54Z

1

I believe that your problem is that your url is not percent-encoded. You need to use the stringByAddingPercentEncodingWithAllowedCharacters: method to do that.

Here is a post that shows you how to do it.

answered Feb 23, 2018 at 13:09

Enrique Bermúdez

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