ruby, how to remove the first part of string?

Question

This is my first time posting in this forum, I am doing some selenium webdriver testing, I collected some data from an html UI, put it in an array:

consents = $driver.find_elements(:xpath,"//*[@id='main-display']/div[2]/div[2]/div/table/tbody/tr/td[7]//i")

, then I processed the array with map :

consent_values = consents.map { |consent| consent.attribute('class')}

printing the array I got :

["fa fa-check-circle", "fa fa-circle-thin", "fa fa-check-circle", "fa fa-circle-thin", "fa fa-circle-thin", "fa fa-check-circle", "fa fa-circle-thin", "fa fa-circle-thin", "fa fa-check-circle,....]

1) Is there a way to do in the map to remove "fa" from all strings in the array ?

2) How about changing the strings "fa fa-check-circle" to be true and "fa fa-circle-thin" to be false so I will get : [true,false,true,....]

Thanks,

1) One way to do it is by using String#sub with a Regexp as pattern. 2) What prevents you do that? — axiac
– axiac, Commented Feb 27, 2018 at 14:29
I got it, I used string[N..-1] , was wondering if can change the strings to true or false in the map transformation. — Fatna
– Fatna, Commented Feb 27, 2018 at 14:55
There's a thread here that goes into detail on removing the start of a string. Might find it good reading. — SRack
– SRack, Commented Feb 27, 2018 at 15:36

Aleksei Matiushkin · Accepted Answer · 2018-02-27 14:48:07Z

1

Basically 2) eliminates the necessity of 1), so here you go:

consent_values = consents.map do |consent|
  case consent.attribute('class')
  when "fa fa-check-circle" then true
  when "fa fa-circle-thin" then false
  else nil
  end
end

To remove "fa " prefix from the string one might use String#[]:

"fa fa-check-circle"[/(?<=\Afa ).*/]
#⇒ "fa-check-circle"

answered Feb 27, 2018 at 14:48

Aleksei Matiushkin

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3 Comments

Fatna Over a year ago

I like this answer too, I will go try it.

RAJ Over a year ago

@Fatna This one has the clear answer for you because you can completely eliminate one step.

SRack Over a year ago

Didn't know you could do that with String#[]. Informative as ever, +1. (I also like 2.5.0's delete_prefix for readability.)

Fatna · Accepted Answer · 2018-02-27 14:57:55Z

0

string[N..-1]

This worked for me. thanks anyway, I hope I will interact with this forum lot.

answered Feb 27, 2018 at 14:57

Fatna

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1 Comment

RAJ Over a year ago

Hi, Have a look at @mudasobwa 's answer, he has written an answer which actually reduces one step for you!

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