Delete key present inside objects array via jq

Question

If I want to delete age from the JSON in first output. Is there a way to do that in one step, in other words, not invoking jq 2 times?

➜ $?=0 @arastogi-ld2.linkedin.biz inGraphs/common-templates [ 1:39AM] ➤ echo '[{"id": 1, "name": "Arthur", "age": "21"},{"id": 2, "name": "Richard", "age": "32"}]' | jq .
[
  {
    "id": 1,
    "name": "Arthur",
    "age": "21"
  },
  {
    "id": 2,
    "name": "Richard",
    "age": "32"
  }
]

>>>  0s elasped...
➜ $?=0 @arastogi-ld2.linkedin.biz inGraphs/common-templates [ 1:39AM] ➤ echo '[{"id": 1, "name": "Arthur", "age": "21"},{"id": 2, "name": "Richard", "age": "32"}]' | jq '.[] | del(.age)' | jq -s
[
  {
    "id": 1,
    "name": "Arthur"
  },
  {
    "id": 2,
    "name": "Richard"
  }
]

>>>  1s elasped...
➜ $?=0 @arastogi-ld2.linkedin.biz inGraphs/common-templates [ 1:39AM] ➤

Inian · Accepted Answer · 2018-03-06 10:05:24Z

10

It is quite simple when using jq using the map() call.

jq 'map(del(.age))' < json

Using map() for a given filter del(.age) will run it for each element of the input array, and return the output in a new array.

edited Mar 6, 2018 at 10:05

answered Mar 6, 2018 at 9:51

Inian

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