I'm looking for a regex to remove trailing zeros from decimal numbers. It should return the following results:
0.0002300 -> 0.00023
10.002300 -> 10.0023
100.0 -> 100
1000 -> 1000
0.0 -> 0
0 -> 0
Basically, it should remove trailing zeros and trailing decimal point if the fraction part is 0. It should also return 0 when that's the value. Any thoughts? thanks.
Try the regex:
(?:(\..*[^0])0+|\.0+)$
and replace it with:
\1
A demo:
tests = ['0.0002300', '10.002300', '100.0', '1000', '0.0', '0']
tests.each { |tst|
print tst, " -> ", tst.sub(/(?:(\..*[^0])0+|\.0+)$/, '\1'), "\n"
}
which produces:
0.0002300 -> 0.00023
10.002300 -> 10.0023
100.0 -> 100
1000 -> 1000
0.0 -> 0
0 -> 0
Or you could simply do "%g" % tst to drop the trailing zeros:
tests = ['0.0002300', '10.002300', '100.0', '1000', '0.0', '0']
tests.each { |tst|
s = "%g" % tst
print tst, " -> ", s, "\n"
}
which produces the same output.
Here is bit more optimized regex solution.
Search for this regex:
(?:(\.[0-9]*[1-9])|\.)0+$
and replace with:
\1
RegEx Details:
(?:: Start non-capture group
(\.[0-9]*[1-9]): Match a dot followed by 0+ instances of any digit and then a digit 1-9. Capture this value in group #1 (to be used in replacement back-reference \1)|: OR\.: Match a dot): End non-capture group0+: Match 1+ of zeroes$: End