How do I deserialize a JSON array without needing a wrapper type? [duplicate]

Question

I want to deserialize the following JSON:

[
  {
    "name": "one",
    "path": "/path/to/one"
  },
  {
    "name": "two",
    "path": "/path/to/two"
  },
  {
    "name": "three",
    "path": "/path/to/three"
  }
]

Into a Vec<Worskpace>. Workspace is defined below:

#[derive(Serialize, Deserialize)]
struct Workspace {
    name: String,
    path: String,
}

Is there a way to do that without having to do something like:

#[derive(Serialize, Deserialize)]
struct Workspacesss {
    values: Vec<Workspace>,
}

What part of your proposed solution do you not like? How would you use your Workspacesss? — Shepmaster
– Shepmaster, Commented Mar 6, 2018 at 20:24
@Shepmaster You're right. I thought that getting a Vec<Workspace> was tricky because what is deserializable (done by me) is Workspace. Turns out serde_json already got Vec's covered. — sargas
– sargas, Commented Mar 6, 2018 at 20:36

Shepmaster · Accepted Answer · 2018-03-06 20:21:18Z

4

Just deserialize the vector directly:

let workspaces = serde_json::from_str::<Vec<Workspace>>(input);

answered Mar 6, 2018 at 20:21

Shepmaster

439k116 gold badges1.3k silver badges1.5k bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

sargas Over a year ago

I'm a fool for not understanding the serde API.

Collectives™ on Stack Overflow

How do I deserialize a JSON array without needing a wrapper type? [duplicate]

1 Answer 1

1 Comment

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Linked

Related