How to turn String to String array?

Question

How to write a programme that can store names and id using JOptionpane i tried storing String but the result comes up with String cannot be converted to String[]??

import javax.swing.JOptionPane;
public class TestWorker {
public static void main(String args[]) {
 int amount = Integer.parseInt(JOptionPane.showInputDialog(null, "How many Would you like to enter?"));
    String[] storedname = new String[amount];
    storedname = JOptionPane.showInputDialog(null,"Whats the First persons name?");
    Workers(storedname);
}
public static void Workers(String[] Workername){
    System.out.println("The name of the First Worker is " + Workername);

 }
}

Possible duplicate of How to use JOptionPane to input data into an array — DontKnowMuchBut Getting Better
– DontKnowMuchBut Getting Better, Commented Apr 1, 2018 at 15:40
showInputDialog() allows entering one name, and getting back the result, as one string. So, since you want N names, you need a loop, asking for one name at each iteration, and storing each of them in the array. You need to read a bit more about loops, and about arrays. The Java tutorial is your friend. — JB Nizet
– JB Nizet, Commented Apr 1, 2018 at 15:43

Jose Martinez · Accepted Answer · 2018-04-01 15:46:35Z

0

The problem might be with the Workers method requiring an input of String[] but you are passing it a String.

Can you change the Workers method to require a String instead of a String[], like the example below?

public static void Workers(String Workername){



    System.out.println("The name of the First Worker is " + Workername);

 }

answered Apr 1, 2018 at 15:46

Jose Martinez

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Armando Perez · Accepted Answer · 2018-04-01 15:45:06Z

-3

I could not understand the explanation of your question to be honest. But, I will answer based on the title question. Also, this is a question answered before in another StackOverflow thread. Anyways, you can do it like this:

String[] args = "your string".split(" ");

You put inside the split method, the string flag that the method will use in order to break the string into string[].

For more info visit: string to string array conversion in java

answered Apr 1, 2018 at 15:45

Armando Perez

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