Combine array and insert differences

Question

Say i have two objects, object_one

{
  1: {item1 /*updated*/}, //note updated represents more recent item1 data
  2: {item1 /*updated*/},
  3: {item1 /*updated*/}
}

and object_two

{
  1: {item1, item2, item3},
  2: {item1, item2, item3},
  4: {item1, item2, item3},
  5: {item1, item2, item3}
}

I want to add the object_one into the object_two, adding any elements that the object_two doesn't have. I also want to take the object_two's versions of item1 and update them to the value of object_one's

Desired result

{
  1: {item1 /*updated*/, item2, item3},
  2: {item1 /*updated*/, item2, item3},
  3: {item1 /*updated*/},
  4: {item1, item2, item3},
  5: {item1, item2, item3}
}

I've tried doing it myself, but my solution was manual and didn't work for all lengths of object_one and object_two. Some direction would be much appreciated

@CertainPerformance its just pseudo code, ment to represent that the smaller object's values are more recent — Ryan Turnbull
– Ryan Turnbull, Commented Apr 3, 2018 at 6:02
the question is how can we think item1(updated)===item1 so item1(updated) don't need to update?because they both have string item1? — xianshenglu
– xianshenglu, Commented Apr 3, 2018 at 6:05

Arman Charan · Accepted Answer · 2018-04-03 06:26:19Z

3

See Object.entries and Object.assign for more info.

// Original.
const original = {
  1: {A: '1A', B: '1B', C: '1C'},
  2: {A: '2A', B: '2B', C: '2C'},
  4: {A: '4A', B: '4B', C: '4C'},
  5: {A: '5A', B: '5B', C: '5C'}
}

// Merge.
const update = {
  1: {A: '1A updated'},
  2: {B: '2B updated'},
  3: {C: '3C updated'}
}

// Combine.
const merge = (original, update) => {
  const x = {...original}
  Object.entries(update).forEach(([key, value]) => {
    x[key] = Object.assign({}, x[key], value)
  })
  return x
}

// Output.
const output = merge(original, update)

// Proof.
console.log(output)

edited Apr 3, 2018 at 6:26

answered Apr 3, 2018 at 6:08

Arman Charan

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