Python question on threads

Question

I am trying to run two thread concurrently on two function like the ones listed below :

import threading

def functionA():
    for i in range(5):
        print "Calling function A"

def functionB():
    for i in range(5):
        print "Calling function B"

t1 = threading.Thread(functionA())
t2 = threading.Thread(functionB())

t1.start()
t2.start()

Results :

Calling function A Calling function A Calling function A Calling function A Calling function A Calling function B Calling function B Calling function B Calling function B Calling function B

But unfortunately after trying out several times. I am not able to get the result

The Desired results :

Calling function A Calling function B Calling function A Calling function B Calling function A Calling function B Calling function A Calling function B Calling function A

Can someone guide me so that the two threads can run concurrently at the same time and produce the desired results. Thanks in advance.

user395760 · Accepted Answer · 2011-02-11 13:17:41Z

2

You're calling the functions and pass the result to the Thread constructor instead of passing the function. Also, you must use the target argument (instead of the unused group which comes first). Just use Thread(target=functionA) and Thread(target=functionB). Note the lack of parens after the functions.

Note that you still won't get multithreading in CPython, but that's a different question.

answered Feb 11, 2011 at 13:17

user395760

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Comments

Community · Accepted Answer · 2017-05-23 10:33:12Z

@delnan already answered how to use Thread correctly, so I'm going to focus on what you want the desired output to be.

You will most likely NOT be able to get the desired output that you want. The timing of when threads execute is not guaranteed, especially in Python. The OS scheduling can impact when each thread gets to run. When running two threads like this, you're effectively saying "these two pieces of work do not depend on the order of each other and can be run at the same time".

You could get output like this:

 a,a,b,b,a,a,b,b,a,b

Or:

 a,b,b,b,b,b,a,a,a,a

It will change on every execution of your program. Do NOT rely on the order of thread execution!

Threading in Python is a dangerous beast. No two threads are ever running within Python at exactly the same time. Read up on the Global Interpret Lock for more information.

utdemir · Accepted Answer · 2011-02-11 13:35:37Z

0

You are writing a new thread, the operating system takes care of how threads use the processor. That's why the sorting isn't regular. You should use another varible to define which function has turn. But still a bad idea.

answered Feb 11, 2011 at 13:35

utdemir

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Comments

abduls85 · Accepted Answer · 2011-02-11 14:59:14Z

0

It will be great if python 3.2 is release as looking at the link below there are built in libraries that can help me achieve my goals.

http://docs.python.org/dev/library/concurrent.futures.html

But nevertheless will look into the alternative provided by other helpful memebers. Thanks for the help provided once again.

answered Feb 11, 2011 at 14:59

abduls85

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