Execute python file from another python file by passing argument as variable

Question

In the below code, I am trying to take the path name (inclusive of file name) and converting them to another path name with text file.

Now I would like to pass both variable as argument for another py which will take it as argument

import os

thisdir=[os.path.join(r,file) for r,d,f in 
os.walk("C:\\Users\\vnitin\\OneDrive - NetApp Inc\\IDP\\Files\\") for file 
in f]
for i in range(len(thisdir)):
    text_path = thisdir[i].replace('pdf', 'txt')
    print(text_path)
    os.system('py pdf2txt.py -o text_path thisdir[i]')

But individual command for pdf2txt.py works very well.

py .\pdf2txt.py -o 'C:\Users\vnitin\OneDrive - NetApp Inc\IDP\Files\11.txt'  
'C:\Users\vnitin\OneDrive - NetApp Inc\IDP\Files\11.pdf'

Perhaps you should have a look to the subprocess module: docs.python.org/3/library/subprocess.html#module-subprocess — Adonis
– Adonis, Commented Apr 9, 2018 at 8:57
os.system('py pdf2txt.py -o text_path thisdir[i]') this executes as a string, so your i is not what you expect it to be — Chen A.
– Chen A., Commented Apr 9, 2018 at 9:00

Abhishake Gupta · Accepted Answer · 2018-04-09 09:13:26Z

1

since thisdir[i] is not converted to its value during execution, so the error No such file or directory

Replace os.system('py pdf2txt.py -o text_path thisdir[i]') with

os.system("python ./pdf2txt.py -o {0} {1}".format(text_path,thisdir[i]))

edited Apr 9, 2018 at 9:13

answered Apr 9, 2018 at 8:55

Abhishake Gupta

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4 Comments

Nitin Over a year ago

No it doesn't I am getting IOError: [Errno 2] No such file or directory: 'thisdir[i]'

Nitin Over a year ago

Now this. IOError: [Errno 13] Permission denied: 'C:\\Users\\vnitin\\OneDrive' Not sure, why permission denied, because it works very well with the full path as argument.

Abhishake Gupta Over a year ago

Unsure of the permission denied error, can you check the file permissions?

Nitin Over a year ago

Hi. it worked. I gave some better path and it went fine. Thanks a lot for quick help :)

Hari · Accepted Answer · 2018-04-09 09:01:03Z

0

Two Solutions: 1)You can directly import and call the main method with params

data = pdf2txt.main(['pdf2txt.py',filename])

or

2) Form a string and pass it as a command

    string ="py .\pdf2txt.py -o" +" C:\Users\vnitin\OneDrive - NetApp Inc\IDP\Files\11.txt"+" C:\Users\vnitin\OneDrive - NetApp Inc\IDP\Files\11.pdf"

answered Apr 9, 2018 at 9:01

Hari

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1 Comment

Nitin Over a year ago

about the first point, after import pdf2txt and running the first option, it is giving error ImportError: cannot import name 'maxint

Abhishake Gupta · Accepted Answer · 2018-04-09 09:14:28Z

0

Use SubProcess module

import subprocess
subprocess.Popen("python ./pdf2txt.py -o {0} {1}".format(text_path,thisdir[i])", shell=True)

Now, stdin, stdout, and stderr can also be redirected.

answered Apr 9, 2018 at 9:14

Abhishake Gupta

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