The issue is that the webservice does not have the fileupload data. Here is the full code from our extended conversation:
[WebMethod]
public static string InsertUpdateMWSiteData(MWInsertUpdateFields MWInsertUpdateFields)
{
string strInsertUpdateMWInfo = "";
try
{
Dashboard dshb = new Dashboard();
dshb.CreateFilePath(MWInsertUpdateFields.SapID + "_" + MWInsertUpdateFields.CandidateID);
strInsertUpdateMWInfo = CommonDB.InsertUpdateMWSiteInfo(MWInsertUpdateFields);
}
catch (Exception)
{
throw;
}
return strInsertUpdateMWInfo;
}
public string CreateFilePath(string addedFolderName)
{
string folderPath = ConfigurationManager.AppSettings["DocDirectory"].ToString();
string FileUplPath = folderPath + "\\" + addedFolderName + "\\";
if (!Directory.Exists(FileUplPath))
{
Directory.CreateDirectory(FileUplPath);
}
if (flUploadDoc.HasFile == true)
{
string strFilename = Path.GetFileName(flUploadDoc.FileName);
flUploadDoc.SaveAs(FileUplPath + Path.GetFileName(flUploadDoc.PostedFile.FileName));
}
return folderPath;
}
The problem is that after uploading a file, a request is sent to a webmethod which is being hosted in another instance of the program. This Webmethod checks its own instance for the fileupload control and data, and doesn't find it because it is in a different instance. This is why your fileupload control is returning null even on a sanity check of .HasFile().
One solution is to pass the data to the Webservice. You could for example pass the data to your webmethod as a byte[], and then on the webservice side reconvert it back into its original file type. After completing this process, save the file to your local filesystem. To do this you may need to pass the extension type and file name.
You may also want to add some validation to limit the file types accepted to only the most common file types like images, .doc, .excel, and whatever you have the library to support the conversion of.
If you want to save files directly to your filesystem using the upload control, you can do so but you will have to exclude the webservice step.
Please also see the discussion in chat for details.
Path.GetFileName(flUploadDocs.FileName)