Loop error for multiple conditions

Question

I have this loop:

puts "Welcome to the Loop Practice Problems"
puts " Write a number between 1 and 10, but not 5 or else...."
ans = gets.chomp!
if ans < 1
  puts "Tf bruh bruh"
elsif ans > 10
  puts "Now you just playin"
elsif x == 5
  print "You wildin B"
else
  puts "Fosho that's all I require"
end

It doesn't run properly, and I'm trying to understand why. If you can help me with this, I'd appreciate it.

If you know a good site for practice problems, I'd love to try it. I checked out Coderbyte and Code Kata, but the way they're set up doesn't look right, and they don't have questions to solve for fundamentals.

You also have a typo in elsif x==5 should be elsif ans==5 — Subash
– Subash, Commented Apr 27, 2018 at 0:34
Is there any significance in using print just under the third branch? — sawa
– sawa, Commented Apr 27, 2018 at 3:49
You can start practicing ruby: codecademy.com/courses/learn-ruby/lessons — A J
– A J, Commented Apr 27, 2018 at 3:52

Ryan Bigg · Accepted Answer · 2018-04-27 00:29:21Z

3

The issue here is that you're not converting ans to a number, but you're comparing it to one. ans is going to be a string.

In Ruby, when you compare a number to a string, Ruby says that the two aren't equal:

"1" == 1
=> false

You can reproduce the problem with this code:

puts "Welcome to the Loop Practice Problems"
puts " Write a number between 1 and 10, but not 5 or else...."

ans=gets.chomp!
p ans

The p method will output an "inspected" version of that object, (it's the same as doing puts ans.inspect). This will show it wrapped in quotes, which indicates that it's a string.

You probably want to do this:

ans = gets.chomp!.to_i

The to_i method here will convert the number to an integer, and then your comparisons will work correctly.

answered Apr 27, 2018 at 0:29

Ryan Bigg

108k25 gold badges243 silver badges264 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Stefan Over a year ago

And you probably want chomp (without !) since the bang variant might return nil.

Aleksei Matiushkin Over a year ago

@Stefan you probably do not want chomp at all, since "1\n".to_i #⇒ 1 :)

vipin · Accepted Answer · 2018-04-27 06:53:24Z

0

You have to convert input string type object into integer type

ans = gets.chomp!.to_i #input string convert into integer.
if ans < 1
  puts "Tf bruh bruh"
elsif ans > 10
  puts "Now you just playin"
elsif x == 5
  print "You wildin B"
else
  puts "Fosho that's all I require"
end

answered Apr 27, 2018 at 6:53

vipin

2,5101 gold badge22 silver badges37 bronze badges

Collectives™ on Stack Overflow

Loop error for multiple conditions

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related