File:
C:\Some\Location\index
I just want to replace \index with \example
echo preg_replace('/[\\\|\/]{1}.*?$/', '\example', $file);
It just keeps being too greedy. I don't know of any modifiers that would help that problem.
Thanks!
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5 Answers
how about echo preg_replace('/[\\\|\/]{1}[^\\\/]*?$/', '\example', $file); ?
Comments
Replace the . with [^/\], which matches anything but the slashes. I also changed the regex delimiter to @, since slashes aren't appropriate when handling paths.
$str='C:\\Some\\Location\\index';
echo preg_replace('@[/\\\\][^/\\\\]+$@', '\example', $str);
# echoes: C:\Some\Location\example
Comments
You don't need a regex for that if you can use forward slashes instead of those ugly backslashes (yes, windows does support forward slashes):
$str = 'C:/Some/Location/index';
echo dirname($str).'/example';
3 Comments
Senica Gonzalez
Well, I can't assume that any platform uses one or the other as far as slashes go, unless I'm replacing slashes, but that seems unnecessary. @simon, I think regular expressions are very appropriate here.
simon
@Senica - to perform path manipulation? I'm gonna stick to my original opinion.
ThiefMaster
You do not need backslashes on any platform. Forward slashes are the way to go. They work on Linux/Unix, OSX and Windows - and probably on most/all exotic systems.
preg_replace( '/(^.*?)\\([^\\]+)$/', '$1\\example', $file );
And a RegExp-less solution:
$path = explode( '\\', $file );
array_splice( $path, -1, 1, 'example' )
$file = implode( '\\', $path );
Comments
If you insist on using regular expressions,
echo preg_replace('/[^\/\\]*$/', 'example', $file)
will do.
I recommend using
echo dirname($file).'\example'
instead, which will safely handle forward and backslashes, the root directory etc.
