Execute shell command line in java to get a variable

Question

i'm trying to get the version variable and display my current app version in my user interface

the commande line looks like this :

ls -l

total 24

lrwxrwxrwx 1 username 33 Sep 15 2016 current -> /dir1/dir2/dir3/current-app-version

i would like to know how to get that "current" variable

can anyone explain for me and guide me

it's my first time doing something like this Thanks in advance :)

Eby Jacob · Accepted Answer · 2018-05-05 16:10:43Z

1

from Java open the file /dir1/dir2/dir3/current-app-version and read the content, it will show the current version if its present in the file current-app-version

else if the app version is the file name, then from java access the file in dir3 and use that in java code.

answered May 5, 2018 at 16:10

Eby Jacob

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schmaeddes · Accepted Answer · 2018-05-04 12:24:16Z

0

That "current" is no variable. It is just a symbolic link, like a link to an Applikation in Windows.

Is there any content in that file /dir1/dir2/dir3/current-app-version? Try:

cat /dir1/dir2/dir3/current-app-version

answered May 4, 2018 at 12:24

schmaeddes

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1 Comment

Jeizi Over a year ago

yes there is 3 files , and yes current is just a symbolic link as u said , it represents the current version of the app when u clic on it, it will have the current version as a file name and u will find those 3 files in it, and i just wanted to know how can i get that current version in my java code to display it in my front interface

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