All possible combinations in adding elements of list c#

Question

namespace CombinationWork
{
    class Program
    {
        static void Main(string[] args)
        {
            List<int> List = new List<int>(new int[] {1,2,5,10});
            for (int noSelected=0;noSelected<4;noSelected++)
            {
                for(int noAdded=0;noAdded<4;noAdded++)
                {
                    List.Add(List[noSelected]+List[noAdded]);
                }
            }
            List = List.Distinct().ToList();
            for (int display = 0; display < List.Count; display++)
            {
                Console.WriteLine( List[display]);
            }
            Console.ReadLine();
        }
    }
}

Guys assistance needed. let say i have an array: int[] a={1,2,5,10}; I want to add all the elements with each other .Example:

1
2
2+1=3
5+1=6
5+2=7
5+2+1=8
10
10+1=11
10+2=12
10+2+1=13
10+5=15
10+5+1=16
10+5+2=17
10+5+2+1=18

I'm getting some inaccurate values. The error lies in using the nested for loops but i dont know what else to use

Ashokan Sivapragasam · Accepted Answer · 2018-05-06 09:17:32Z

1

For n numbers, it should give you 2 pow n combinations. Use binary representation of numbers to publish all combinations.

Example, Binary - 001 decimal - 1 Binary - 010 decimal - 2 Binary - 011 decimal - 3 ... Binary - 001 decimal - 1

From above truth table, include a number to summation only when respective binary digit is 1

Example, your numbers in list [1, 2, 3]; interpret as follows, For Binary - 001, you should get 3 For Binary - 010, you should get 2 For Binary - 011, you should get 2 + 3 = 6

answered May 6, 2018 at 9:17

Ashokan Sivapragasam

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