PHP: Parse url from css property

Question

I have a string from css (background property):

$sStr = 'url(http://www.ser.com/styles/../img/big-logo.gif) 10px 0 no-repeat';

Now I need the url of the image file like this:

'http://www.server.de/styles/../media/visuals/big-logo.gif'

Thanks for help

user557846 · Accepted Answer · 2011-02-16 19:52:35Z

1

preg_match("/\((.*)\)/",  $sStr,  $matches);
print_r($matches);

answered Feb 16, 2011 at 19:52

user557846

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Comments

simshaun · Accepted Answer · 2011-02-16 20:05:47Z

0

It can be done a couple different ways, but in my opinion the easiest is regex.

if (preg_match('/url\(([^)]+)\)/i', $subject, $regs)) {
    $result = $regs[1];
} else {
    $result = "";
}

answered Feb 16, 2011 at 19:54

simshaun

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@Ilyssis $regs[1] is what you want in this version