I am taking a integer input from a function and the operation such as "+10" from the user and printing the result after computation. So far i have this
def Eval(arg1, arg2):
if (arg1 >= 100):
arg1 == 100
else:
arg1 = eval((arg1)(arg2))
print arg1
Eval(10,'+10')
But I have TypeError: 'int' object is not callable error. Can someone tell me where i am doing wrong?
You can use ast.literal_eval. This is recommended instead of eval due to security concerns.
from ast import literal_eval
def Eval(arg1, arg2):
if (arg1 >= 100):
arg1 == 100
return literal_eval(str(arg1)+arg2)
x = raw_input('Append string to variable for calculation:\n') # '+10'
res = Eval(10, x)
print res # 20
The issue comes from attempting to pass eval an int and a str when it only accepts a str. You could solve this by combining arg1 and arg2, after converting arg1 to a str.
arg1 = 10
arg2 = '+1'
evalInput = str(arg1) + arg2
eval(evalInput)
>> 11
This could be made cleaner by using string formatting, but this should give you a general idea.
