Phoenix Framework / Elixir, output relative file path to the console

Question

How to log the relative file location to its project root?

"my-project" is the root directory of the Phoenix Framework project. Inside users/me/apps/my-project/my-file.txt, if I do :

IO.puts __ENV__.file

The console outputs the absolute path: users/me/apps/my-project/my-file.txt.

How to output the relative path, e.g. my-project/my-file.txt ?

Dogbert · Accepted Answer · 2018-05-09 18:30:15Z

3

You can fetch the root directory using File.cwd!() and then do a leading trim of __ENV__.file with it:

defmodule A do
  def a do
    __ENV__.file |> String.trim_leading(File.cwd!)
  end
end

Sample output:

iex(1)> A.a
"/lib/a.ex"

answered May 9, 2018 at 18:30

Dogbert

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2 Comments

looshi Over a year ago

is File.cwd! always the "project" directory ( where the app was compiled ), or is it the directory where the compiled app is running ?

Dogbert Over a year ago

File.cwd! at run time will point to the directory you're running mix from. If you want it to always point to its own project's root (which I think you do), you can call the function at compile time: @cwd File.cwd!() and then use @cwd.

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