Sending url using ajax on codeigniter

Question

I have this Ajax script where I pass a link to the data variable link, but I

get a 412 error.

$(function() {
  $(".check-multi").change(function() {
    $.ajax({
      type: "POST",
      url: "<?php echo site_url('adm/updateproperty'); ?>",
      async: true,
      data: {
        link: $(this).data('link')
      },
      success: function(msg) {
        alert('Success');
        if (msg != 'success') {
          alert('Fail');
        }
      }
    });
  });
});

I have tried

link: encodeURI($(this).data('link'))

And

link: encodeURIComponent($(this).data('link'))

as is suggested on other threads but I still get the 412 error message.

always accept answer by ticking it as green if you find it helps you — Pradeep
– Pradeep, Commented May 13, 2018 at 0:24
@pradeep Thanks. None of the answers solved my issue... I ended up removing the http:// part of the before sending it and adding it server side. Thats why I didn't checked any of the answers. — Cool Guy
– Cool Guy, Commented May 14, 2018 at 19:42

Pradeep · Accepted Answer · 2018-05-12 05:49:51Z

1

Hope this will help you :

you have added newline character to json data that is why you got error

Do like this :

var link = $(this).data('link');
data: {"link" : link},

/*----OR do this -----*/

data: {"link" : $(this).data('link')},

instead of this :

data: {
        link: $(this).data('link')
      },

Whole code should be like this :

var link = $(this).data('link');
/*console.log(link)*/
$.ajax({
      type: "POST",
      url: "<?php echo site_url('adm/updateproperty'); ?>",
      async: true,
      data: {"link" : link },
      success: function(msg) {
        alert('Success');
        if (msg != 'success') {
          alert('Fail');
        }
      }
    });

For More :https://developer.mozilla.org/en-US/docs/Web/HTTP/Status/412

answered May 12, 2018 at 5:49

Pradeep

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Comments

Pradosh Mukhopadhayay · Accepted Answer · 2018-05-12 06:21:57Z

1

Please change your code in data options. Use this way

data: {"id": ID},

i.e. store the value in a variable and send that variable in data option. If we assume

ID=$(this).data('link');`

Then the code will be as follows:

$(function() {
  $(".check-multi").change(function() {
    $.ajax({
      type: "POST",
      url: "<?php echo site_url('adm/updateproperty'); ?>",
      async: true,
      data: {"id":ID},
      success: function(msg) {
        alert('Success');
        if (msg != 'success') {
          alert('Fail');
        }
      }
    });
  });
});

Please check it.

edited May 12, 2018 at 6:21

answered May 12, 2018 at 5:19

Pradosh Mukhopadhayay

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2 Comments

Ankit Singh Over a year ago

What's the difference? Changing name of variable?

Pradosh Mukhopadhayay Over a year ago

There is no difference in changing the variable name. I want to tell you that you do your code in this way. first assign the value in a variable i.e. ID=$(this).data('link'); then send the value on that way.

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