So what i want is for my code to understand if my input has a number in it or not, if it does it is meant to output "Correct" but if it doesn't then it would output "Incorrect" how can i actually make this work. So it knows if there is an integer in the input or not. Any help is appreciated
import re
yourString=input()
number = re.search(r'\d+', yourString).group()
if number == True:
print("Correct")
else:
print("Incorrect")
According to https://docs.python.org/3/library/re.html#match-objects you have a bit of a subtle error.
The statement should not be if number == True: it should be if number:, the reason being the value number is tests as True if anything is matched, and is None if there are no matches.
i.e.
import re
yourString=input()
number = re.search(r'\d+', yourString)
if number:
print("Correct")
group = number.group()
else:
print("Incorrect")
Note, somewhat bizarrely
import re
yourString=input()
number = re.search(r'\d+', yourString)
if number:
print(number == True)
group = number.group()
else:
print("Incorrect")
Prints false, so number is not the value true, it overrides __bool__. See https://docs.python.org/3/reference/datamodel.html#object.bool for more information
if number: resolves to true, even in that block if you add print number == True that will print false, but the test function of the number object has been overridden. This is unusually complex functionality btw.You can use str.isdigit, re.search, or the built-in string to number conversions such as float and int:
def extractNumber(string):
for word in string.split():
try:
# The float() function accepts a decimal string.
# The int() function accepts an integer string.
return float(word)
except ValueError:
pass
number = extractNumber(input())
if number is not None:
print('Your number is: {}'.format(number))
else:
print('No number found')
\d+ will match one to many occurrences of digits, then it will detect floats
float function above.the regex you're looking for is: \w*[0-9]+\w*. It accepts anything that contains at least one digit.
\w* is the same as [a-zA-Z0-9_]* meaning it will match any lower/upper -case letter, digit or _ literally. It can occur 0 to many times in the string
[0-9]+ matches one to many digits from 0 to 9.
Actually, if your intention is just to check whether the string has digits you are good to go just with [0-9]+ that's the same of what you posted originally.
You can try and create regexes using this site regex101.com
