Rename multiple images randomly from a list of keywords using python 2.7

Question

I am trying to rename multiple images using os.rename() in Python from a list keyword_name randomly so I break it into these steps:

def keyword()
- keyword_name a list that holds keyword
- loop through list
- assign a variable that holds the index(list[])

import os
keyword_name = "key.jpg","alph.jpg","hold.jpg","name.jpg","kid.jpg",
"young","zolo","lima0","sofia","temra","tooad","aeder","ed","de","cf","fc"
def keyword():
    index = 0
    while index < len(keyword_name):
        keyword = keyword_name[index]
        print(keyword)
        index += 1

def rename_name()
- returns a list containing the names of the entries in the directory given by path.
- returns current working directory of a process.

def renam_name():
        file_list = os.listdir(r"C:\Desktop\cLine\file")
        saved_path =os.getcwd()
        os.chdir(r"C:\Desktop\cLine\file")
    for f in file_list:
        #spilt text to file_name,img_type
        file_name, img_type = os.path.splitext(f)
        #convert the tuple to a list
        keyword = list(file_name)
        #join the list 
        name = "".join(keyword)
        print(name)
        os.rename(name, keyword_name)

I am new to programming. I did some research, but I only found how to remove integers or a string from file_name. I'll be so thankful if somebody can help me.

The sources I've been looking at:

Rename multiple files in a directory in Python

Rename multiple files in Python

What is the purpose of the keyword method()? Because it just prints each item from the keyword_name and increments an unused index. Did you intend to get a random name from keyword and use it for os.rename? — Gino Mempin
– Gino Mempin, Commented May 18, 2018 at 2:22
yes that exactly what i am trying to do os.rename(name, keyword_name) but i got stuck how to bring keyword[index] +1 and store it to a variable and change to str — lamnaouer
– lamnaouer, Commented May 18, 2018 at 2:25

Gino Mempin · Accepted Answer · 2018-05-18 02:56:26Z

There are many parts of your code that aren't needed.

The keyword method should randomly select a keyword from keyword_name.
Then, call it to provide the 2nd argument to os.rename.

Try this (I placed comments inline):

import os
import random


# Use a list instead of a tuple so that we can modify
keyword_name = ["key","alph","hold","name","kid", "young","zolo","lima0","sofia","temra","tooad","aeder","ed","de","cf","fc"]


def keyword():
    # Generate a random index
    rand_index = random.randint(0, len(keyword_name)-1)

    # Get the keyword 
    rand_keyword = keyword_name[rand_index]

    # Remove the used-up keyword from the list to
    # prevent randomly selecting it again when renaming
    keyword_name.remove(rand_keyword)

    return rand_keyword


def renam_name():
    os.chdir(r"<path-to-image-folder>")
    file_list = os.listdir(r"<path-to-image-folder>")
    for f in file_list:
        # get the file extension
        file_name, img_type = os.path.splitext(f)   

        # Call the random keyword generator then use the return
        # value as the new file name. 
        os.rename(f, keyword() + img_type)


renam_name()

In addition, since keywords are chosen at random, you'll have to prevent selecting the same keyword, so that the code will not rename the file to a previously renamed file. To do this, I remove the already-chosen keyword from keyword_name (I needed to change keyword_name to a list because tuples are immutable).

It might be also better to remove the ".jpg" extensions from the keyword_name list, as those will produce new filenames like "name.jpg.png".

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