How to open file in java and parse each line

Question

I have a text file containing data like this:

sender id: 1/sequence number: 0/depth: 600/sending time: 13/05/2018 11:17:17 ص/data: Hello I am AUV: 1 this is aggregation # 0 from my sideEnd-End Delay:0.357072263241232 sender id: 0/sequence number: 0/depth: 700/sending time: 13/05/2018 11:17:17 ص/data: Hello I am AUV: 0 this is aggregation # 0 from my sideEnd-End Delay:0.293693984840975 sender id: 2/sequence number: 0/depth: 500/sending time: 13/05/2018 11:17:17 ص/data: Hello I am AUV: 2 this is aggregation # 0 from my sideEnd-End Delay:0.421466419584594 sender id: 3/sequence number: 0/depth: 400/sending time: 13/05/2018 11:17:17 ص/data: Hello I am AUV: 3 this is aggregation # 0 from my sideEnd-End Delay:0.486473186901286 sender id: 3/sequence number: 1/depth: 400/sending time: 13/05/2018 11:17:18 ص/data: Hello I am AUV: 3 this is aggregation # 1 from my sideEnd-End Delay:0.486473186901286 sender id: 1/sequence number: 0/depth: 600/sending time: 13/05/2018 11:17:21 ص/data: Hello I am AUV: 1 this is aggregation # 0 from my sideEnd-End Delay:0.32221205728025 sender id: 0/sequence number: 0/depth: 700/sending time: 13/05/2018 11:17:21 ص/data: Hello I am AUV: 0 this is aggregation # 0 from my sideEnd-End Delay:0.267329486404354

Each line ends with the end-end delay, for example line#1:

sender id: 1/sequence number: 0/depth: 600/sending time: 13/05/2018 11:17:17 ص/data: Hello I am AUV: 1 this is aggregation # 0 from my sideEnd-End Delay:0.357072263241232

I need to divide this file into others files where each file corresponding to a specific sender id.

Each file will contain the end-end delay values for each sender id only such as 0.357072263241232.

I have 4 senders so 4 files will be generated ...

Any help or any hint please ?

I don't have the experience with regex!

Question: Are you certain that each line does not already end in a newline or carriage return? — Tim Biegeleisen
– Tim Biegeleisen, Commented May 20, 2018 at 16:10
each line end by a new line and at the end of each line there is a double value ... — isra
– isra, Commented May 20, 2018 at 16:17

Matt.G · Accepted Answer · 2018-05-20 16:18:58Z

1

Try Regex: sender\sid:\s(\d+).*?End-End\sDelay:(\d+(?:\.\d+)?)

Demo

Group 1 will have the sender id

Group 2 will have the end - end delay value

answered May 20, 2018 at 16:18

Matt.G

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2 Comments

isra Over a year ago

How to use it with open file method and store the result in the correct file with append option?

Matt.G Over a year ago

I'm afraid, I'll not be able to help you much with the exact Java code. This link could be a starting point for you

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