Kotlin: Log.i() printing only 2 elements from 53-element array

Question

I want to iterate through my ArrayList named parts, here is my code:

for(x in parts.indices){
            Log.i("INFO", parts.indices.toString())
        }

The output is the following:

0..52
0..52

But I'd expect 0..52 to be printed 53 times. I've tried changing x in parts.indices to x in 0 until parts.size, but the output remains the same. Interestingly enough, when I use the same construction in another class with the same imports it works ok. What am I doing wrong?

Your problem is not reproducible. It's probably on the level of log output, not program logic. (0..52).toList().also { parts -> for (x in parts.indices) println(parts.indices) } -- prints 0..52 53 times. — Marko Topolnik
– Marko Topolnik, Commented Jun 1, 2018 at 12:01
What's the reason for iterating over indices instead of using parts.forEach()? — Pawel
– Pawel, Commented Jun 1, 2018 at 14:25
@Pawel I just need the indices to perform some calculations later on — K.W.
– K.W., Commented Jun 1, 2018 at 15:42

K.W. · Accepted Answer · 2018-06-01 15:45:58Z

1

It is a Log issue, as noted by @Marko Topolnik, it seems to be 'folding' the output when strings are identical. Println does it as well, but at least prints a message saying 'identical 51 lines'.

answered Jun 1, 2018 at 15:45

K.W.

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