I am learning JavaScript, so if this question is nonsense correct me.
function greaterThan(n) {
return m => m > n;
}
let greaterThan10 = greaterThan(10);
console.log(greaterThan10(11));
// → true
In this function is there is any possible way to call inside function m=> m > n along with " greaterthan " function ?
Like greaterthan(10(11)); 🤔 where I provide m and n both variables ?
This is how you do that
greaterThan(10)(11);
As greaterThan(n) returns a function, so you are just calling that function passing some parameters
function greaterThan(n) {
return m => m > n;
}
console.log(greaterThan(10)(11)); There is a way to reduce functions of more than one argument to functions of one argument, a way called currying
Here is an interesting blog to read about currying
That function is curried, meaning that it takes one argument at a time and returns new, partially applied function until all the arguments were provided. If you want to execute such function while passing all the arguments at once, then you need to uncurry it first.
For that, you need either some library that provides uncurry function or you can write your own.
function uncurry(f) {
if (typeof f != "function" || f.length == 0) { return f; }
return function() {
var r = f;
for (var i = 0; i < arguments.length; i++) { r = r(arguments[i]); }
return r;
};
}
function greaterThan(n) {
return m => m > n;
}
const greaterThanUnc = uncurry(greaterThan);
console.log(greaterThanUnc(10, 11));