Selenium can't find element which is visible

Question

This is HTML where I try to find selected input

I try to sendkey() to this input like this

String xPath = "//*[@id='id_username']";

WebDriverWait wait = new WebDriverWait(driver, 30);

wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath(xPath))).sendKeys("text");

Always get this error org.openqa.selenium.TimeoutException. Usually I get this error when element is not visible in setted time.

There is no iframe in entire html.

Which may be the cause?

There are two possible reasons. 1) Duplicate xpath. 2) May be extra popup is open while entering text into input box. — Vinit Mehta
– Vinit Mehta, Commented Jun 6, 2018 at 13:21
When you write Xpath in developer console , then how many entries are present ? Have you tried to include both presenceofelement and visibilityofelement — cruisepandey
– cruisepandey, Commented Jun 6, 2018 at 13:40

undetected Selenium · Accepted Answer · 2018-06-06 13:52:11Z

1

You need to consider a couple of points as follows:

Instead of String try to define the xpath as an object of By.
Moving forward as you are invoking sendKeys() instead of ExpectedConditions method visibilityOfElementLocated() use elementToBeClickable() method.
As the element is an <input> try to construct a granular xpath

Your code block will be as:

By xPath = By.xpath("//form[@action='/accounts/register/']/fieldset[@class='fieldset_main']//input[@id='id_username' and @name='username']");
new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(xPath)).sendKeys("text");

edited Jun 6, 2018 at 13:52

answered Jun 6, 2018 at 13:30

undetected Selenium

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4 Comments

KunLun Over a year ago

How element can be clickable if it is not visible? By the way, real problem was duplicate xpath. There was another input with same id but in a div with display:none, and all of this was above my input.

undetected Selenium Over a year ago

Give it a try and let me know the status

KunLun Over a year ago

Your code work, because you settled in which segment of code to looking for input, and there is no duplicate input.

undetected Selenium Over a year ago

Of-coarse that should be the ideal approach through getting granular

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