Write a function, which would return a list with the strings and their index. e.g. ['good', 'morning'] -> ['0 - good', '1 - morning']
I tried this:
def add_index(list_a):
x = []
for word in list_a:
x = [list_a.index(word) for word in list_a]
return x
However, the return is [0, 1], not what I am looking for.
You can use enumerate function:
>>> def f(data):
... return ['{} - {}'.format(i, s) for i, s in enumerate(data)]
...
>>> f(['good', 'morning'])
['0 - good', '1 - morning']
If you are in python 3.6+ you can also use f-strings:
>>> def f(data):
... return [f'{i} - {s}' for i, s in enumerate(data)]
...
>>> f(['good', 'morning'])
['0 - good', '1 - morning']
x = []
for word in list_a:
x = [list_a.index(word) + ' - ' + word for word in list_a]
return x
Your list comprehension is only pulling the index and not the word:
x = ["{} - {}".format(list_a.index(word), word) for word in list_a]
Try doing this:
for index, word in enumerate(list_a):
print(str(index) + " - " + word)
This will add an index number for every topic in list_a. That index is then added into a string printing it. If you want it to be added to a new list I would do like this.
x = []
for index, word in enumerate(list_a):
x.insert(len(x), str(index) + " - " + str(word))
