Below is my code :
public class prg34 {
public static void main(String[] args) {
int a=6;
for(int i=0;i<10;i++){
System.out.println(a/i);
}
}
}
Exception:
Exception in thread "main" java.lang.ArithmeticException: / by zero at run.prg34.main(prg34.java:8)
How to solve above Arithmetic Exception in java ?
You are trying to divide by zero in your first iteration. Change your first condition of i = 0, to something other than zero.
You cannot divide by 0, as I believe Java handles the division by zero error by a processor exception which triggers an interrupt.
Your first iteration is trying 6/0.
public static void main(String[] args) {
int a=6;
for(int i=1;i<10;i++){
System.out.println(a/i);
}
}
The first loop in your code gives an exception because you are trying to divide 6 by 0 i.e the ArithmeticException.
In order to fix this you must have to use try catch block. I've illustrated full code here. Please fix this.
public class prg34 {
public static void main(String[] args) {
int a=6;
try {
for(int i = 0; i < 10; i++) {
System.out.println(a/i);
}
}catch(ArithmeticException e) {
System.out.println("Division by zero is not possible. "+ e);
}
}
}
