I really don't have a clue how to increase variables by using function with an argument. Code down below prints 0 and 1 and i understand why but i don't know how to fix it. It's just a general 'shape' of a code, so there can be any number of variables. Will appreciate if you take a look!
i=0
b=0
def increase(a):
print(a)
a+=1
print(a)
for e in range (3):
increase(i)
increase(b)
Python does not have parameters reference like c++ ( the & sign ), so you can use a returning function.
i=0
b=0
def increase(a):
print(a)
a+=1
print(a)
return a
for e in range (3):
i = increase(i)
b = increase(b)
There's a somewhat lengthy discussion surrounding why you can't do what you're trying to do the way you're trying to do it, but the accepted answer here should be useful to you. Essentially, all arguments in Python are passed by object reference, so if you reassign the value in your function using the name of the parameter you are not changing the value pointed to by the variable you passed to your function.
What you're trying to do is possible, you just need to pass your function a mutable type, like a list. So, if you have the following code, it should do what you expect/want from your example:
i=[0]
b=[0]
def increase(a):
a[0]+=1
for e in range (3):
increase(i)
increase(b)
print(i)
print(b)
global aat the beginning ofincreasefunction. Using global variables is bad for your code, bla-bla...void increase(int* a) { (*a)++; } increase(&i);